On 11-07-05 10:20 AM, Dajka Tamás wrote:
Hi,
Yeah, I'm really want to do that, since I'm working with the elements of the
original array ( skipped that part in sample code ).
I've tried your suggestion, but it gives the same result, so on just one input
is just gives back '1'.
Ahhh... you want the behaviour of the multiple elements... I presumed
you wanted the other way around.
What troubles me, that foreach gives an inconsistent working. Why is 'foreach'
checking element count at all and working differently with different element
counts? That's not normal is my opinion. 'foreach' shouldn't do this:
if ( count($elements) == 1 ) then loop 1;
else loop normally;
and that's what is does now, since when it's more than one element it's working
like a while loop, with checking the condition before ( and after ) every run.
( if 'foreach' would check that the current run is the last one before
executing the current loop, the results would be the same with each case )
You're making an assumption that it is checking the count. It may just
be pre-determining whether another element exists for the next
iteration. Consider the following pseudo code:
nextItem = items->reset();
while( nextItem )
{
item = nextItem;
nextItem = items->next();
// Do stuff.
}
There's lots of ways to program a loop... and your PHP foreach loop is
being converted to something entirely different internally. The above
doesn't count elements, but it will result in the same behaviour as you
are experiencing.
Cheers,
Rob.
--
E-Mail Disclaimer: Information contained in this message and any
attached documents is considered confidential and legally protected.
This message is intended solely for the addressee(s). Disclosure,
copying, and distribution are prohibited unless authorized.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php