Here's something I use for a date string that looks like mm/dd/yyyy to
turn the date into an age from the current date.
$age = explode("/", $bdate);
$userage = date("Y") - $age[2];
if($age[0] > date("m") || ( $age[0] == date("m") && $age[1] > date
("d"))) { --$userage; }
if($userage > 50) { $userage = ""; }
I did not compensate for leap years, however. You could use my code,
and it should work fine, but the first line where I do an explode,
you'd have to change that to turn your date string into #'s like I
use..
>
> does any one know where i can get a script that will convert a
birthdate in to an age. i have one half written however i have
incounter difficulties with dealing with leap years. perhaps soem one
would know the solution . .. or just a premade script is fine
>
>
> $test = strtotime ("January 12, 1944");
> $test2 = strtotime ("January 9, 1954");
>
> $oneyear = 3600 * 24 * 365;
>
> $diff = $test2 - $test;
> $ans = $diff/$oneyear;
>
> echo $ans;
>
>
>
>
>
> Thank You,
>
> Jon Yaggie
> www.design-monster.com
>
> And they were singing . . .
>
> '100 little bugs in the code
> 100 bugs in the code
> fix one bug, compile it again
> 101 little bugs in the code
>
> 101 little bugs in the code . . .'
>
> And it continued until they reached 0
>
>
>
>
Corey Chapman
Xnull CEO
(Chat with us: http://forum.xnull.com)
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