What are you getting? An image at all? Broken image?
Try getting rid of the header("image/jpeg") or whatever, and see if you have
some error message.
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----- Original Message -----
From: Hugh Danaher <[EMAIL PROTECTED]>
Newsgroups: php.general
To: Php-General <[EMAIL PROTECTED]>
Sent: Tuesday, August 21, 2001 1:16 AM
Subject: if statement and imageline()
help,
I am trying to set up a .jpg file to graph the earnings per year of a
company. I can generate a log-normal graph, can get it to display the
earnings per year as circles on the graph, but I can't get the " if () "
statement to work. I know I am setting two of the variables in the if
statement after the if statement executes once, but these variables won't be
used until after the " for () " loops once, and therefore should be
available for use in " imageline() " on the second loop (where
$year>$startyear). Somehow, I think my logic is correct but it mustn't be
so.
$startyear=1996;
$chart_start_year=1992;
for ($year=$startyear;$year<=$startyear+7;$year++)
{
$x=(($year-$chart_start_year)*20)+20;
$y=420-log(${"earnings_".$year})*75;
if ($year>$startyear)
{
imageline($image,$first_x,$first_y,$x,$y,$blue);
}
$first_x=$x;
$first_y=$y;
imagettftext($image,9,0,$x_distance-4,$y_distance+3,$blue,$font2,"m");
}
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