I didn't take the time to read your code too thoroughly, but remember to
have your select name to be anything with "[]" at the end of it, from the
look of your name field you have something inside the [], you need to get
rid of the rec_pd4 and just call it "x[]" or whatever you would like to call
it as long as the "[]" is empty :) I hope that made sense!
Rick
> From: Tom Beidler <[EMAIL PROTECTED]>
> Date: Fri, 14 Sep 2001 17:26:50 -0700
> To: php list <[EMAIL PROTECTED]>
> Subject: [PHP] multiple selections in list/menu field
>
> I'm trying to use a list/menu field with multiple options allowed but I'm
> only getting the very last selection.
>
> Here's part of my code to build the list/menu field;
>
> print (" <td><select name=\"x[rec_pd4]\" multiple size=\"15\">\n");
> print ("$option_pd4");
> print (" </select></td>\n");
>
> Here's the code to build the options;
>
> $pd4arry = array(array("c1,","Bookpacks & Daypacks"),array("c2,","Mini
> Packs/Diaper Bag"),array("c3,","Shoulder Bags/Briefcase"));
> foreach($pd4arry as $value) {
>
> if (($value[0] == $category_code) || ($value[0] == $x[rec_pd4])) {
> $option_pd4 .= " <option
> value=\"$value[0]\"selected>$value[1]</option>\n";
> } else {
> $option_pd4 .= " <option
> value=\"$value[0]\">$value[1]</option>\n";
> }
> }
>
> The field displays fine but I only get the last option. I'm testing with IE
> 5.
>
> Let me know if this is not a PHP issue but I thought there might be
> something that would prevent me from using this type of field with PHP.
>
> Thanks,
> Tom
>
>
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