Could it be the semi colon at the end of the 'if' line, at '... $nChar =
45); { ...' ? Looks like the if statement ends there, the ' { print
"OK."; } ' is a block on it's own and the 'else' is now out of context.
-----Original Message-----
From: Brad Melendy [mailto:[EMAIL PROTECTED]]
Sent: Friday, October 19, 2001 8:03 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Can I have If...Else inside a For Loop???
Hi All,
I'm stumped. I've got the following code:
<?php
if(isSet($domain))
{
for ( $counter=0; $counter <= strlen($domain); $counter++ )
{
$nChar = ord(strtolower(substr($domain, $counter, 1)));
if (($nChar > 47 And $nChar < 58) or ($nChar > 96 And $nChar < 123) or
$nChar = 45);
{
print "OK.";
}
else
{
print "Not OK.";
}
}
}
?>
What's got me beat is that this code fails on the ELSE statement. Now, if I
comment out the ELSE statement, the code proceeds, I just don't get the
results I want when the coditions in IF statement are false.
Anyone know what I'm doing wrong? It's as if you can't nest an IF/Else
under a FOR, but you can use just an IF. Thanks very much in advance.
....Brad
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