In article <[EMAIL PROTECTED]>, [EMAIL PROTECTED] (Ricardo Fitzgerald) wrote:
> *print '<td width="25%" bgcolor="#FcaF00"><b><font face="Tahoma, Verdana, > Arial, Sans Serif">Ref:</font><b/></td>';* > *print '<td width="25%" bgcolor="#FFFF00"><b><font face="Tahoma, Verdana, > Arial, Sans Serif">$reference</font><b/></td>';* > > the problem is with the output, the table is fine but the variable $reference > otputs it's name $reference instead of it's value i.e. 345. I'm getting mad > because I know this has to be some kind of syntax error but I tried > exchanging quotes for double quotes, adding parenthesis and stuff like that > and I couldn't figure out what the prob is ... Re-try the double quotes. Variable expansion is available within double quotes. It is not within single quotes. -- CC -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
