read this page a little closer!
http://www.php.net/manual/en/function.mysql-fetch-array.php

the mysql_fetch_array();  does not pull all the results in one big array.
it IS only a single row of data.

try this out, it should do what you are looking to do.

$results = mysql_query("SELECT * FROM models WHERE lang='$lang' AND
key1='data' AND key2='$series'",$db);

while ($models = mysql_fetch_array($results))
{
    echo $models ."<p>";
}



Jim
----- Original Message -----
From: "René Fournier" <[EMAIL PROTECTED]>
To: "Php-General" <[EMAIL PROTECTED]>
Sent: Thursday, November 08, 2001 2:25 PM
Subject: [PHP] Array HELP PLEASE


> (Before you write RTFM, please know that I have checked www.php.net,
> zend.com, phpbuilder.com, et all, and--in the eternal words of Bono--I
still
> haven't found what I'm looking.)
>
> The situation:  I extract an array from a MySQL table. Code:
>
> $models = mysql_fetch_array(mysql_query("SELECT * FROM models WHERE
> lang='$lang' AND key1='data' AND key2='$series'",$db));
>
> Based on the above criteria, there should be two rows in $modelsrow, with
> each row containing about twenty elements.  (A two-dimensional array,
> right?)  All I want to do is display the contents of $models.   With the
> following...
>
> for ($i = 1; $i <= 20; $i++) {
> echo $models[$i]."<p>";
> }
>
> ...I get just one row.  How can I also display the other row?  I've tried
> variations of $models[1][2], but I just can't get right syntax.  (Help is
> much appreciated. Thanks.)
>
> If you know of a good tutorial on multidimension arrays + mySQL, that
would
> be nice too.
>
> ...Rene
>
>
> --
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