Hi guys, I know that you can take todays date and display it as the numeric day of the year, 1 - 365 / 0 - 364 etc. But can you take a date such as (November-30-1971) and convert that to the numeric day of the year?
I have been trying to do this but have had no joy, I don't think my code is even close. $dob = getdate("Nov-30-1971"); $dobnum = $dob['yday']; print $dobnum; $dob 'should' be an array and 'yday' should be the numeric value for the day of the year, right?!? This is what I am trying, and how I understand it, using 'yday' should give you basically the same output as date ("z"); What I would like is the ability to convert any date to the days numeric value. Any help would be GREATLY appreciated. (C: -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]