I tried but nothing different happened.  I'm still playing though and I'll
see if I can make it work.  I'm new to all of this...so we'll see how it
goes.  Thanks for your help.

-jordan


Fred <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Strings in your sql query must be quoted.  Try this instead:
>
> >    $result = mysql_query("SELECT * FROM ar
> >    LEFT JOIN company on ar.company_id=company.company_id
> >    LEFT JOIN scale on ar.scale_id=scale.scale_id
> >    WHERE item_number = \"$item[$index]\")";
>
> Fred
>
> Jordan <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > here's the situation.  I'm making a shopping cart, when an item is added
> > it's item number is added into an array.  I then want this array's items
> to
> > be compared agains the database.  Unfortunately I haven't been able to
use
> a
> > variable in the query string of MySQL.  something along the lines of....
> >
> >
> > <?PHP
> >
> >    include ('connect.php');
> >
> >    $result = mysql_query("SELECT * FROM ar
> >    LEFT JOIN company on ar.company_id=company.company_id
> >    LEFT JOIN scale on ar.scale_id=scale.scale_id
> >    WHERE item_number =" . $item[$index]);
> >
> > ?>
> >
> > where $item is the array of item numbers and $index is an auto
> incrementing
> > number that increments at the end of the loop.  Please help if you know
of
> > anyway to use this variable.  Also, I can post my whole script if
> needed...I
> > just didn't want unneeded info posted.  Thanks in advance.
> >
> > -Jordan
> >
> >
>
>



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