Ivo Stoykov wrote in [EMAIL PROTECTED]:">news:[EMAIL PROTECTED]:
> Hello again
>
> earlier today I asked about detecting whether javascript is
> enabled on the visitor's browser (bellow are the question and
> answeres received).
<html>
<head>
</head>
<body>
<script type="text/javascript">
jsImg = new Image()
jsImg.src = "js-yes.gif";
</script>
<noscript>
<img src="js-no.gif" width="0" height="0" alt="" />
</noscript>
</body>
</html>
Your access logs for the images js-yes.gif, and js-no.gif will give
you stats over js/no-js.
If you need something more sophisticated, you can replace js-yes.gif
and js-no.gif with serverside scripts that add the results to a
database.
I have a sample php-script that gives you some of that functionality
without resorting to database:
[jsenabled.php]
<?php
if ($js_=="y"){
$file = "ay.txt";
} else if ($js=="n"){
$file = "an.txt";
}
$fp = fopen($file,"a");
fwrite($fp,"1");
fclose($fp);
header("Content-type: image/gif");
readfile("spacer.gif");
?>
I then modify the html/js code to look like this:
[somedocument.html]
<html>
<head>
</head>
<body>
<script type="text/javascript">
jsImg = new Image()
jsImg.src = "jsenabled.php?js=y";
</script>
<noscript>
<img src="jsenabled.php?js=n" width="0" height="0" alt="" />
</noscript>
</body>
</html>
Please note that you'd want to purge the an.txt and ay.txt every once
in a while.
--
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Newsere mot X-No-Archive
<URL:http://www.ibiblio.org/Dave/Dr-Fun/df9601/df960124.jpg>
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