No, with your syntax it won't. You have to quote it in the query, as in $query2 = "select * from Table where userNo = $userNo and clientID = '$clientID'";
Bogdan Brad Wright wrote: > Thanks, > > $clientID is a string but is not empty...already tried echo($clientID) and > it is not empty. > > Did you mean that if the value of $cientID is a string it wont work???? > > Thanks > Brad > > > From: Bogdan Stancescu <[EMAIL PROTECTED]> > > Date: Mon, 11 Feb 2002 05:38:31 +0200 > > To: Brad Wright <[EMAIL PROTECTED]> > > Cc: PHP General List <[EMAIL PROTECTED]> > > Subject: Re: [PHP] 2 conditions why wont they work?? > > > > Do an echo($clientID) before - it most probably is either empty or it's a > > string and MySQL actually issues errors there. > > > > Bogdan > > > > Brad Wright wrote: > > > >> Hi all, > >> Im was sure you could select a row from a mySQL database based on 2 > >> conditions. My code: > >> > >> $query2 = "select * from Table where userNo = $userNo and clientID = > >> $clientID"; > >> $result2 = mysql_query($query2,$db); > >> > >> This returns : > >> Warning: Supplied argument is not a valid MySQL result resource > >> > >> b ut if i change the line to: > >> $query2 = "select * from Table where userNo = $userNo; > >> $result2 = mysql_query($query2,$db); > >> > >> it works (but get all the rows with userNo = $userNo. > >> > >> HELP!!!! Im sure this should work...what am i doing wrong??? > >> > >> -- > >> PHP General Mailing List (http://www.php.net/) > >> To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
