as a said before i'm not sure; my idea was to use type casting instead of
eregi;
anyone can develop it into smart solution; i am out of time now for this
developing
so can suggest idea only

Valentin Petruchek (aki Zliy Pes)
*** cUT THE BEGINNING ***
http://zliypes.com.ua
mailto:[EMAIL PROTECTED]
----- Original Message -----
From: "Daniel Kushner" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Cc: "PHP" <[EMAIL PROTECTED]>
Sent: Tuesday, February 12, 2002 4:00 PM
Subject: RE: [PHP] ereg-digits only...


> That wouldn't work!
> 1) You meant to write: if (((int)$string==$string) && ($string>0))
>
> 2) (int)'5a' == 5, so this formula would result is 5a == 5!
>
> --Daniel
>
>
> > -----Original Message-----
> > From: val petruchek [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, February 12, 2002 6:22 AM
> > To: [EMAIL PROTECTED]
> > Cc: PHP
> > Subject: Re: [PHP] ereg-digits only...
> >
> >
> > if ((int($string)==($string)) && ($string>0)) {then positive integer}
> >
> > not sure exactly, but try
> >
> > Valentin Petruchek (aki Zliy Pes)
> > *** Cut the beginning ***
> > http://zliypes.com.ua
> > mailto:[EMAIL PROTECTED]
> > ----- Original Message -----
> > From: "B. Verbeek" <[EMAIL PROTECTED]>
> > To: "Php-Db-Help (E-mail)" <[EMAIL PROTECTED]>; "Php-General
(E-mail)"
> > <[EMAIL PROTECTED]>
> > Sent: Tuesday, February 12, 2002 1:04 PM
> > Subject: [PHP] ereg-digits only...
> >
> >
> > >
> > > How do I check a string for it to only contain numbers?
> > >
> > > >>
> > >
> > >   if(!ereg("([0-9]+)",$string)){
> > >
> > >     print "It contains characters other than numbers";
> > >
> > >   }else{
> > >
> > >     print "Only numbers";
> > >
> > >   }
> > >
> > > <<
> > >
> > > Can anyone give some feedback...
> > >
> > > regards,
> > > Bart
> > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
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> > >
> > >
> >
> >
> >
> >
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