Here's a little piece of code that gives me a weird problem:
<?php
if (!$logout)
{
if ($_SESSION['loggedin'])
{
unset($_SESSION['loggedin']);
}
}
?>
I have the session started and everything, but it gives me the following
error.
Warning: Undefined variable: logout in c:\inetpub\wwwroot\uslogin.php on
line 13
I've seen this used on several examples. I know that if I just use
empty($logout) then it'll work ok, but I just wanted to know why it's used
in so many examples but doesn't work in my code. Is there some setting that
I have set wrong or something? Thanks,
Dave
"David Johansen" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I'm new to this php thing and I would like to set up a web page were the
> users can login and edit their preferences and all that stuff. I have the
> basic login stuff worked out and I was passing the username and password
as
> a hidden input in the form, but then the password can be seen with view
> source. I know that there's a better way to do this, so could someone
point
> me to a good tutorial or example on how I could make it so that the user
> could login and logout and then I wouldn't need to be passing the password
> all around like this. Thanks,
> Dave
>
>
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