It still just comes out blank when the vars is wrong....

"R'Twick Niceorgaw" <[EMAIL PROTECTED]> wrote in message
020501c1d01b$11eb1d00$[EMAIL PROTECTED]">news:020501c1d01b$11eb1d00$[EMAIL PROTECTED]...
> You need two = signs for comparision not just one .
> Also I think you need to enclose the variables in double quote.
>
>        if( $line[1]=="$bruker" and $line[2]=="$passord")  echo "hei
> $bruker.";
>          else echo "FEIL";
>
>
> > -----Original Message-----
> > From: chris [mailto:[EMAIL PROTECTED]]
> > Sent: Wednesday, March 20, 2002 8:15 AM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP] why doesnt this work???
> >
> >
> > this script receives vars "b" and "p" from a form.
> > If "b" and "p" matches the echo on IF, then it works just fine.
> > The problem is that if the vars dont match the ELSE ECHO
> > does not apear... why not?
> >
> > <?
> > $bruker = $HTTP_POST_VARS["b"];
> > $passord = $HTTP_POST_VARS["p"];
> > $hostname = "********";
> > $username = "********";
> > $password = "********";
> > $dbname = "********";
> > MSSQL_CONNECT($hostname,$username,$password);
> > mssql_select_db($dbname);
> > $query = "select * from medlemmer where bruker = '$bruker' and passord =
> > '$passord'";
> > $result = mssql_query( $query );
> > for ($i = 0; $i < mssql_num_rows( $result ); ++$i)
> >      {
> >
> >       $line = mssql_fetch_row($result);
> >       if( $line[1]='$bruker' and $line[2]='$passord')  echo "hei
> $bruker.";
> >          else echo "FEIL";
> >      }
> > ?>
> >
> > -Chris
> >
> >
> >
> > --
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> >
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> >
> >
>
>



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