in fooa.php for each textfield <? if (!empty($field1)) $value=$value; else $value=""; ?>
<input type="text" name="textfield" value="<?echo $value;?>"> so, when you come back from foob.php if a $field !empty the respective textfiel will have a value in html form; -- Best regards, George Nicolae IT Manager ___________________ PaginiWeb.com - Professional Web Design www.PaginiWeb.com "Simos Varelakis" <[EMAIL PROTECTED]> wrote in message 000401c1d9a2$afd6bde0$9b00a8c0@simos">news:000401c1d9a2$afd6bde0$9b00a8c0@simos... Here is a problem :-) A php post form fooa.php Submit all form fields to a page foob.php Page foob.php do some mysql db check and in one condition I want to Return to fooa.php without losing any field value... I made this from foob.php with header:("location:fooa.php?field1=$field1&field2=$field2.....etc") But this is more complex esspecially when in fooa.php there are radio buttons + checkboxes. I thing that if I could with Javascript in foob.php create an (invisble) form and take all posted fields from Fooa.php And resubmit it with form.submit method to fooa.php I will have best results But I don’t know how to do this since I am a begginer.. Anyone can help please send me an email Thanks in advnace for your time & help and excuse me if is off topic Best Regads simos -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
