if the output of graph.php is a URL, your code should work.
<img src="/images/mypic.jpg">
if graph outputs the image itself, you have to do it a bit different:
in the html it should look like:
<img src="graph.php?...">
and graph.php should do something like:
header("Content-Type: image/gif");
echo $imagecontent;
Hope that helps
Michael
"Moschitz Martin" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> What is wrong with the following statement? The Picture which is generated
> in graf.php is not displayed.
>
> echo "<img src=";
> include(" graf.php ");
> echo ">";
>
> thanxs
> martin
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