> function somefunction($myvar) {
> do something...
> ...
> ...
> return \$myvar;
> }
>
> $varname = somefunction($myvar);
> echo "$varname";That won't work, because you escaped the $ sign, the variable won't get processed and the name returned will be the one of the variable as it is declared in the function, always the same. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
