and i'd suggest using eregi instead, because then also .Jpg or .JPG will be found.
"Michael Virnstein" <[EMAIL PROTECTED]> schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > see what's wrong here: > ereg('(^[0-1231]$).jpg$',$file_name) > > [] meens a group of characters, so in your case > 0,1,2 and 3 are valid characters. you haven't defined any > modifer like ?,*,+ or{}, so one of this characters has to > be found exactly one time. you're using ^ outside the [] so it meens the > beginning of the string. > in your case none of these characters inside the [] can be found at the > beginning of the string. > then you use $ after the []. $ meens the end of the string. none of the > characters in the [] matches at the end of the string. > so this would be right: > > ereg('_[0-9]{4}\.jpg$', $file_name); > > so this meens: > the beginning of the string doesn't matter, because we have not specified ^ > at the beginning. > there has to be an underscore, followed by 4 characters between 0 and 9, > followed by an dot, > followed by j, followd by p, followed by g. g has to be at the end of the > string, because of the $. > or you can use: > ereg('^\.*_[0-9]{4}\.jpg$', $file_name); > > this will meen : > any characters at the beginning between 0 and unlimited times, then followed > by an underscore, > followed by 4 characters between 0 and 9, followed by a dot, followed by > jpg. same as above > though. But the * is a real performance eater so it could be slightly faster > if you're using the first example. > > > > "Jas" <[EMAIL PROTECTED]> schrieb im Newsbeitrag > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > > I hate to say it but that didn't work, I have been trying different > > variations of the same ereg('_(^90-9{4}$).jpg$',$file_names) and nothing > > seems to work for me, I have also been looking at the ereg and preg_ereg > > functions but they don't seem to make sense to me, here is the code as a > > whole if this helps: > > // query directory and place results in select box > > $dir_name = "/path/to/images/directory/on/server/"; // path to directory > on > > server > > $dir = opendir($dir_name); // open the directory in question > > $file_lost .= "<p><FORM METHOD=\"post\" ACTION=\"done.php3\" > NAME=\"ad01\"> > > <SELECT NAME=\"image_path\">"; > > while ($file_names = readdir($dir)) { > > if ($file_names != "." && $file_names !=".." && > ereg('_(^[0-9]{4}.jpg$)', > > $file_names)) // filter my contents > > { > > $file_lost .= "<OPTION VALUE=\"$file_names\" > > NAME=\"$file_names\">$file_names</OPTION>"; > > } > > } > > $file_lost .= "</SELECT><br><br><INPUT TYPE=\"submit\" NAME=\"submit\" > > VALUE=\"select\"></FORM></p>"; > > closedir($dir); > > What I am trying to accomplish is to list the contents of a directory in > > select box but I want to filter out any files that dont meet this criteria > > *_4444.jpg and nothing is working for me, any help or good tutorials on > > strings would be great. > > Jas > > "Erik Price" <[EMAIL PROTECTED]> wrote in message > > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > > > > > > On Thursday, April 11, 2002, at 05:59 AM, jas wrote: > > > > > > > Is this a correct string to show only files that look like so: > > > > *_2222.jpg > > > > if ($file_names != "." && $file_names !=".." && > > > > ereg('(^[0-1231]$).jpg$',$file_name)) > > > > Any help would be great. > > > > > > preg_match(/^_[0-9]{4,4}\.jpg$/, $file_name) should match any string > > > that starts with an underscore, is followed by exactly four digits, and > > > then a ".jpg". It will not match anything but this exact string. > > > > > > > > > Erik > > > > > > > > > > > > > > > ---- > > > > > > Erik Price > > > Web Developer Temp > > > Media Lab, H.H. Brown > > > [EMAIL PROTECTED] > > > > > > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
