I think you can get everything after the ? in the URL with $QUERY_STRING
but I think that it would be a bit dangerous to just accept what's passed, I
think some checking should be done before you use $QUERY_STRING as is

-----Original Message-----
From: Jason Soza [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, April 17, 2002 10:21 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Displaying Results


Sorry, I just noticed that the count() function will do at least the 
first part of my question, i.e. SELECT year, COUNT(*) FROM cars GROUP 
BY year

But the second part still has me a bit stumped. I know that you can 
pass a variable using something like script.php?year=1991, but doesn't 
that assume that in your script you have something like:
$query = ("SELECT * FROM mytable WHERE year=$year")

So the $year is the only variable that gets replaced by the script.php?
year=1991 you called it with. How could I make it so that the 
entire 'year=$year' part of the query gets replaced by what comes after 
the ? in script.php?year=1991  ?

Thanks in advance 
Jason

----- Original Message -----
From: Jason Soza <[EMAIL PROTECTED]>
Date: Tuesday, April 16, 2002 2:49 pm
Subject: [PHP] Displaying Results

> Suppose I want a script that goes into a table, looks up all 
> records in 
> a given field, and groups and displays the results like so:
> match1 (1)
> match2 (5)
> match3 (6)
> 
> So basically it looked at the field 'matches' and found a total of 
> 12 
> records, 1 record for match1, 5 records for match2, and 6 records 
> for 
> match3. It would also be handy for the output to be a link so when 
> you 
> clicked on it, it would pass a query on to the database querying 
> for 
> just that particular field, like:
> SELECT * FROM table WHERE match="match1"
> 
> Can someone point me in the right direction for this? Or show me 
> an 
> example script that would accomplish this? Any help would be 
> great. 
> Thanks a lot!
> 
> Jason
> 
> 
> 
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