RE: [PHP] Listing the contents of a directory in an array

[Jared Boelens]

I actaully had to do that yesterday, here is the code i used.

$path = "/foo/bar";
$myArray = $array();
$dir  = opendir($path);
while($file = readdir($dir)) {
  // if(!ereg("^\.", $file) {
    $myArray[count($myArray)] = $file;
//  }
}
closedir($dir);

If you want to exclude the always present "." and ".." directories just
uncomment those two lines.

-Jared
  -----Original Message-----
  From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
  Sent: Friday, May 17, 2002 8:31 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] Listing the contents of a directory in an array


  I am a newbie so be kind

  I have looked into the manual about directory functions etc.

  I want to return all the files from a directory into a array.

  Could some one give me a few pointers or something?

  I keep getting confused but I have used google and the manual.

  I can find functions but I am not sure how I can list the files into an
array.

  Thanks in advance,

  JJ Harrison
  [EMAIL PROTECTED]
  www.tececo.com