You could try something like this....(did not test)
<?
echo date("Y-m-d");
print $date;
mysql_connect("servername","user","password")
or die("Connect failed");
$query = "select user from log_request where date='$date' and
status = 'open'";
$result = mysql_db_query("call_manage", "$query")
or die("query_failed");
$count=mysql_num_rows($result);
$r=mysql_fetch_array($result);
$user=$r["user"];
print ("<table width=100% border=0><td><tr bgcolor=#f0f0f0>");
print ("<br><b> </b>$count $user<br>\n");
print ("</td></tr>");
-----Original Message-----
From: Chris Grigor [mailto:[EMAIL PROTECTED]]
Sent: Thursday, May 23, 2002 9:48 AM
To: [EMAIL PROTECTED]; Php-General-List (E-mail)
Subject: [PHP] output problem
Howdi Alll
some of you might laugh at this but I cant get this to work....
Im doing a count on a field and want to diplay the result here is an
example...
<?php
#error_reporting(E_ALL);
echo date("Y-m-d");
print $date;
mysql_connect("servername", "user", "password")
or die("Connect failed");
$query = "select count(user) from log_request where
date='$date' and status = 'open'";
$result = mysql_db_query("call_manage", "$query")
or die("query failed");
while($line = mysql_fetch_object($result))
{
print ("<table width=100% border=0><td><tr bgcolor=#f0f0f0>");
print ("<br><b> </b>$line->user<br>\n");
print ("</td></tr>");
}
?>
what am I missing as it returns no value at all from $line->user,
should I be
doing this differently??
Thankyou
Chris
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