Or something easier...
<?
$size = 222;
print <<<HTML
<script language="JavaScript">
width = $size;
</script>
HTML;
?>
Just make sure the "HTML;" bit is all the way on the left margin,
regardless of tabstops in your code.
cheers,
Brad
Boyan Nedkov wrote:
>Try something like that:
>
><?
>//$size = GetImageSize ("images/$resim");
>$size = 222;
>echo "<script language=\"JavaScript\">";
> echo "width="; echo $size; echo ";";
>echo "</script>";
>?>
>
>Cheers, boyan
>
>--
>Boyan Nedkov
>[EMAIL PROTECTED]
>
>
>
>
>>-----Original Message-----
>>From: burak delice [mailto:[EMAIL PROTECTED]]
>>Sent: Monday, May 27, 2002 11:59 PM
>>To: [EMAIL PROTECTED]
>>Subject: [PHP] php's variables & javascript
>>
>>
>>hi everyone,
>>
>>I want to make a php that include javascript that use a php
>>variable. Code is below:
>>
>><?
>>$size = GetImageSize ("images/$resim");
>>echo "<script language=\"JavaScript\">
>> wdth=";$size;echo";";
>> echo "</script>";
>>?>
>>
>>(I am calling that php file as below)
>>http://localhost/Aksu/web/getimage.php?> resim=K00.jpg
>>
>>But
>>explore gives me an javascript error that
>>syntax error. Why? and how can do my purpose?
>>
>>thanks
>>burak delice
>>
>>
>>
>>
>>
>>--
>>PHP General Mailing List (http://www.php.net/)
>>To unsubscribe, visit: http://www.php.net/unsub.php
>>
>>
>>
>
>
>
>
>
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