Hi all, I would say as Jason, and I would add a little remark also even if that doesn't seem to be the pb you have : if (($row = mysql_fetch_array($result)) && ($password==$row["password"]) && ($password ! = ""))
I hope it helps SR Jason Wong a écrit : > On Wednesday 29 May 2002 19:17, Webby wrote: > > When starting a new topic please do not reply to an existing post. Start a new > one. > > > **/ when i run this script it's say parse error in this line 'i don't what > > is wrong with this line > > if (($row = mysql_fetch_array($result)) && > > ($password==$row["password"] && $password ! = "")) > > you probably meant > > ... $password != "" ... > > -- > Jason Wong -> Gremlins Associates -> www.gremlins.com.hk > Open Source Software Systems Integrators > * Web Design & Hosting * Internet & Intranet Applications Development * > > /* > YOW!! The land of the rising SONY!! > */ > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php
