If this is truly the code you're using, you're missing the closing
curly-brace after the else statement. I.e. this:
} else {
echo "<font size=+1>Your Information has successfully been
entered into the database!</font><br>";
Should be this:
} else {
echo "<font size=+1>Your Information has successfully been
entered into the database!</font><br>";
}
HTH,
Jason Soza
----- Original Message -----
From: Jule Slootbeek <[EMAIL PROTECTED]>
Date: Monday, June 3, 2002 2:09 pm
Subject: stupid error, please kick me (and send me a solution)
> Hey guys,
> i'm getting this error with the following sql script using php:
> --error--
> Warning: Supplied argument is not a valid MySQL-Link resource in
> /var/www/phpquiz/register_user.php on line 12
> --error--
>
> --script--
> $link_glob = "mysql_connect('$host_glob', '$un_glob', '$pw_glob')";
> $query = "INSERT INTO user values('0', '$fname', '$lname',
> '$email',
> '$username', PASSWORD('$password')";
> $result = mysql_db_query('$db_glob', '$query',
> $link_glob'); if (!$result) {
> echo "<font size=+1>Your Information
> could not be entered into the database,
> Please contact the
> href=mailto:$webmaster>webmaster.</font><br><br>" . mysql_errno()
> .
> ": " . mysql_error() . "<br><br>";
> } else {
> echo "<font size=+1>Your Information
has
> successfully been entered into the
> database!</font><br>";
>
> --
> Jule Slootbeek
> [EMAIL PROTECTED]
>
> http://blindtheory.cjb.net
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