In that case, split it up into two-steps, to only init the
array if you need to.... i'm not really sure how the rest of
your code is -- you could probably do this a nicer way,
but this will work:
if (!is_array($ary["this"]))
$ary["this"] = array();
$ary["this"]["that"] = 1;
---
Scott Hurring
Systems Programmer
EAC Corporation
[EMAIL PROTECTED]
Voice: 201-462-2149
Fax: 201-288-1515
> -----Original Message-----
> From: Chris Boget [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, June 06, 2002 3:43 PM
> To: Scott Hurring
> Cc: PHP General
> Subject: Re: [PHP] Arrays: Please help before I go insane?
>
>
> > Try: $ary["this"] = array("that" => 1);
>
> That works great until "this" has 2 children. The second child
> overwrites the first. :(
>
> Chris
>
>
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