hi i am populating a list menu with mysql , i would like to find a way to populate a form with more than one of the same list menus in a for loop
<select name="type[]"> <? while ($sample = $result->fetchRow(DB_FETCHMODE_ASSOC)) { $typeID=$sample["typeID"]; $description=$sample["description"]; $sample_type[$sample['typeID']] = $sample["description"]; echo "\n<option value=\"$typeID\" $selected>$description</option>"; } ?> </select> i have this within a for loop but the list only shows up once and the second one is empty because the select from the database is finished , is there a way to put the information from mysql into arrays so i can use it more than once and then i could do multiple populated list boxes ? let me know -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php