$x = preg_replace( "/([^\s&])&([^\s&])/", "$1&&$2", $x ); should do the job. Michael
Neil Freeman <[EMAIL PROTECTED]> schrieb: > Hi, > > For all you Unix gurus this should be run of the mill stuff but us > Windows boys tend to get confused easily :) > > How can I easily match occurrences of text along the lines of R&B and > replace it with R&&B ? > > The regular expression s/&/&&/g obviously replaces any occurrence of an > ampersand with a double ampersand but I need to do a match so that it > only replaces instances which have non whitespace on either side of it, > ie \S&\S > > I think I'm along the right lines but haven't had enough experience with > regular expressions yet to 'finish the job'. > > Hope you can help. > > Neil > > -- > ---------------------------- > Work: [EMAIL PROTECTED] > Home: [EMAIL PROTECTED] > > Web: www.curvedvision.com > ---------------------------- > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
