Thanks Kevin,
Do I need to include 'fclose ($fp);' in there somewhere in this case?
On 7/2/02 3:41 PM, "Kevin Stone" <[EMAIL PROTECTED]> wrote:
> Or just fopen() would work fine.
> -Kevin
>
> ----- Original Message -----
>> Hi :)
>>
>> Given I have some content embedded on my page by calling a remote JS and
>> occasionally the URL for the remote script is down causing my page to be
>> slow or fail, can I use the following example as a means to test and
> timeout
>> the remote server and skip the embedded JS, if the remote server isn't
>> responding properly?
>>
>> <?php
>> $fp = fsockopen ("www.theweathernetwork.com", 80, $errno, $errstr, 5);
>> if (!$fp) {
>> echo "sorry, not available";
>> } else {
>> echo "<script language=\"JavaScript\" type=\"text/javascript\">
>> <!-- var city = \"Muskoka_ON\"; //-->
>> </script>
>> <script language=\"javascript\" type=\"text/javascript\"
>> src=\"http://www.theweathernetwork.com/weatherbutton/test.js\">
>> </script>";
>>
>> }
>> ?>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php