Hi Uwe,
If you define the checkbox list as an array (OptionList[] in the example
below), only the checked values will be returned as an array $OptionList
when you post the form. You can then use this as an array or pass it as an
array to a function in the script:
<?
$i = 0;
while (isset($OptionList[$i])) {
echo "You have chosen option ".$OptionList[$i]."<br>";
$i++;
}
?>
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>
<body bgcolor="#FFFFFF" text="#000000">
<form name="form1" method="post" action="test.php">
<input type="checkbox" name="OptionList[]"
value="something1">Option 1</input><br>
<input type="checkbox" name="OptionList[]"
value="something2">Option 2</input><br>
<input type="checkbox" name="OptionList[]"
value="something3">Option 3</input><br>
<input type="submit" name="Submit" value="Test">
</form>
</body>
</html>
Regards
Rudolf Visagie
Principal Software Developer
Digital Healthcare Solutions
-----Original Message-----
From: Uwe Birkenhain [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 04, 2002 10:53 AM
To: [EMAIL PROTECTED]
Subject: [PHP] How to pass unknown number of variables to a function?
Hi everybody on this rainy morning!
My problem:
I give the user a form with a list of options with checkboxes.
The list is long and not predictable - the values change always.
I want to put the checked values (or all, that doesn't matter) in an array,
to pass it to my function.
How can I write those keys and values in an array?
I suppose it will be best done with JS - but since I don't know JS ...
Has anybody a ready solution?
Thank's a lot!
Uwe
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