This is a continue from this morning (thanks so much for the responses).. yielding a data type mismatch:
$CheckArr = array("Periodic", "Sale", "Return"); IF (SUBSTR($approvalcode,0,1) == "Y" && in_array($CheckArr, $type)) { PRINT "<BR>$approvalcode"; PRINT " "; PRINT "$type"; } This line: IF (SUBSTR($approvalcode,0,1) == "Y" && in_array($CheckArr, $type)) Causes this error: Warning: Wrong datatype for second argument in call to in_array in /home/www/globalspacesolutions/php3/billingtrx.php on line 47 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php