Thank You Andrey, Matt and Martin for your answers.  To summarize for 
everyone, here are the answers:

 From Andrey (tested, works):
for($m=1;$m<=5;$m++){
$div_id[$m]=${'divid'.$m};
}

 From Matt:
for($m=1;$m<=5;$m++){
$varName = 'divId' . $m;
$div_id[$m]=${$varName}
}

 From Martin:
for($i =0; $i < 5; $i++) {
$offset = $m + 1;
$divid[$m] = $div_id{$offset};
}

At 10:55 PM 7/26/2002 +0300, you wrote:


>----- Original Message -----
>From: "Steve Buehler" <[EMAIL PROTECTED]>
>To: "PHP" <[EMAIL PROTECTED]>
>Sent: Friday, July 26, 2002 10:48 PM
>Subject: [PHP] filling an array
>
>
> > Can anyone tell me what I am doing wrong?
> >
> > I am essentially trying to do this:
> > $divid[1] = $div_id1;
> > $divid[2] = $div_id2;
> > $divid[3] = $div_id3;
> > $divid[4] = $div_id4;
> > $divid[5] = $div_id5;
> >
> > But I was looking for a tighter way, like the following (which does not
>work):
> > for($m=1;$m<=5;$m++){
> > $div_id[$m]=$divid$m;
> > }
> >
> > Can anybody tell me how to do this in a "for" statement?
> >
> > Thanks In Advance
> > Steve
> >
> >
> > --
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> > ow3
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
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> >
> >
>
>
>--
>This message has been scanned for viruses and
>dangerous content by MailScanner, and is
>believed to be clean.
>ow3



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