Hello All I am trying to use parse_str in my script , passing a variable.
I have old code, working with php 4.1.2 working with the following script : [root@zion kickstart]# cat make-kickstart.php #!/usr/local/bin/php -q <? // parse any arguments parse_str ($argv[1]) ; print "NAME: $name \n"; ?> for some reason tho , under 4.2.2 it is not parsing the argument/s [root@zion kickstart]# ./make-kickstart.php name=lxmode NAME: Does any one know if anything changed in 4.2.2 , I swear it works under 4.1.2 or older. Thanks for any advice or info in advance !! Cheers Neil -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
