Hello Petre,
There is more than one database to back up so every time it runs
through the while loop it is suppose to back up the next database and
it changes the name of the text file it is sending it to.
I have already tried just doing one database without the while loop
and I get the same results.
So it is not an over writing problem
But Thanks anyway
Monday, September 02, 2002, 12:51:12 AM, you wrote:
PA> put the exec(...) line OUTSIDE the while loop.As your codeis now, it's
PA> dumping with each new row , so i'ts overwriting itself.
PA> On Mon, 2002-09-02 at 09:47, [EMAIL PROTECTED] wrote:
>>
>> I am having a problem with a script to dump a mysql database to a text
>> file. When I run the command below it creates the database.sql file but
>> it only puts the first three lines in that file they look like this
>> # MySQL dump 8.13
>> #
>> # Host: localhost Database: testdata1
>> #--------------------------------------------------------
>> # Server version 3.23.37
>>
>>
>> If I run the following at the command line it work perfect passing the whole
>> database to the txt file
>> /usr/bin/mysqldump -u testdata1 -ptestdata1 testdata1
>> > /home/sites/www.directphp.net/sitebackup/databases/testdata1.sql
>>
>> Why is it stopping on the third line when I run it with a PHP script
>>
>> This is my script
>>
>> while($row = mysql_fetch_array($result)){
>> $databasename=$row["databasename"];
>> $databaseusername=$row["$databaseusername"];
>> $databasepassword=$row["$databasepassword"];
>>
>> exec("/usr/bin/mysqldump -u $databaseusername -p$databasepassword $databasename >
>> $Databasesdir/$databasename.sql");
>> }
>>
>>
>>
>>
>> --
>> Best regards,
>> rdkurth mailto:[EMAIL PROTECTED]
>>
>>
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>>
--
Best regards,
rdkurth mailto:[EMAIL PROTECTED]
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