Martin, so if I write...
function myFunction($name, $phone, $zip="6666"){
echo $name.$phone.$zip
}
and $zip is NOT SET then $zip will = 6666.
But if $zip IS SET then $zip will = whatever $zip's current value is, and will NOT be
changed to 6666?
Please advise.
Thanks Martin
-----Original Message-----
From: Martin Towell [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, September 10, 2002 5:14 PM
To: Shane; [EMAIL PROTECTED]
Subject: RE: [PHP] Easy Function Question?
function myFunction($name, $phone, $zip="6666"){
echo $name.$phone.$zip
}
is the corrent format, but if you call it like this:
myFunction("name", "phone", null);
then $zip will equal null, not "6666"
something like this might help
function myFunction($name, $phone, $zip="6666"){
if (!$zip) $zip = "6666";
echo $name.$phone.$zip
}
HTH
Martin
-----Original Message-----
From: Shane [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 11, 2002 10:14 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Easy Function Question?
I have a need to call a function, where all the variables used might not be
set. Is there a way to have a variable in a function have a default setting
if the variable passed to the function is VOID?
EXAMPLE:
$name="me";
$phone="5555";
//$zip is VOID
function myFunction($name, $phone, $zip){
echo $name.$phone.$zip
}
can I write...?
function myFunction($name, $phone, $zip="6666"){
echo $name.$phone.$zip
}
and then $zip will have a value of 6666 if $zip is VOID for some reason...?
I thought it was something like this, but I keep batting ZERO and there is
no mention of this problem in the places I looked in the docs.
Can anyone throw me a bone?
Thanks gang!
-NorthBayShane
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