I tried that. It gives me 24807, instead of 5. Or is oid is a reference to something else, which would lead me to the '5' i'm looking for?
-- snip snip -- if($result = pg_exec($db, $sql)) { $query = "success"; echo "oid : " .pg_last_oid($result); } -- snip snip -- Sincerely, Faisal -----Original Message----- From: Marek Kilimajer [mailto:[EMAIL PROTECTED]] Sent: Wednesday, September 18, 2002 5:42 PM To: PHP Subject: Re: [PHP] Auto-increment value As he uses postgresql, he should use *pg_last_oid()* Scott Houseman wrote: > Hi there. > > You can use the function mysql_insert_id( [link id] ). > > regards > > Scott > > Faisal Abdullah wrote: > >> Hi people, >> >> I have a table with a column called ID (auto-increment). >> Is it possible to know the value of ID, right after inserting a row? >> I'm using postgresql. >> >> Thanks. >> >> Sincerely, >> Faisal >> >> ______________________________________ >> >> > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php ______________________________________ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php