Hi Heiko Try this: $aName = "TEAM"; eval( '$myString = G_T_'.$aName.';' ); // evaluates to: $myString = G_T_TEAM echo $myString; // Should print out SAFETOUR_team
I haven't tested this, but it should work. Regards Scott On 10/2/2002 10:47 AM, Heiko Mundle wrote: > Hi all, > > my script knows three different constants > > define(G_T_USER, "user_profile"); > define(G_T_TEAM, "SAFETOUR_team"); > define(G_T_CALL, "SAFETOUR_call"); > > Is it possible to get access to them, if I have the names (USER, TEAM, > CALL) in a variable? > > It must be something like that: > > aName = "TEAM"; > myString = "G_T_$sName"; // myString = "SAFETOUR_team" > > > Any hint to solve this problem would be useful. > > heiko > > -- //--------------------------------------------// // Scott Houseman // // Jam Warehouse http://www.jamwarehouse.com/ // // Smart Business Innovation // // +27 21 4477440 / +27 82 4918021 // //--------------------------------------------// -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
