I'm not constructing it with, it is just included in the file. Does that
clarify? Or did I misunderstand your point?
On 11/13/02 1:47 AM, "Ernest E Vogelsinger" <[EMAIL PROTECTED]> wrote:
> You didn't show how you construct the JavaScript string in PHP - I'm sure
> the problem is with quoting in there.
>
> Have a look at your output in the browser (do a "View Source" or whatever
> your Browser calls it), and check the JS your PHP application constructed.
> You'll spot the error...
>
> At 05:28 13.11.2002, Aaron Merrick said:
> --------------------[snip]--------------------
>> Folks,
>>
>> Can't see an answer anywhere in the archives, so here goes.
>>
>> This works fine in plain html:
>>
>> <body onload="start();initialize();onoff('mainmenu',section,'on')"
>> onresize="window.location.reload(false)" topmargin="1" bottommargin="0"
>> leftmargin="0" rightmargin="0">
>>
>> When I put it in PHP thus:
>>
>> echo "<body onload=\"start();initialize();onoff('mainmenu',section,'on')\"
>> onresize=\"window.location.reload(false)\" topmargin=\"1\"
>> bottommargin=\"0\" leftmargin=\"0\" rightmargin=\"0\">";
>>
>> When the page loads, I get an "Error: 'menuObj' is null or not an object"
>>
>> The onoff() function is what contains the menuObj, so I suspect the single
>> quotes around the parameters mainmenu and on, but have tried everyway I can
>> think of and can't get rid of the Error.
>>
>> The function is thus:
>>
>> function onoff (elemparent,elem,state) {
>> if (loaded) {
>> newstate = eval(elem+"_"+state);
>> if (n4) {
>> menuObj = eval (doc + elemparent + doc2 + elem);
>> }
>> else if (ie || n6) {
>> menuObj = eval (doc + elem + doc2);
>> }
>>
>> I would be grateful for any tips.
>>
>> Thanks,
>> Aaron
>>
>>
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> --------------------[snip]--------------------
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