Just a note to keep in the back of your mind.  Unless I'm mistaken MapQuest
prints out road miles to a location.  The formula prints out direct (or as
the crow flies) miles.  There will almost always be differences between the
two.
Fred Steinkopf
----- Original Message -----
From: "Aaron Gould" <[EMAIL PROTECTED]>
To: "Edward Peloke" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Friday, November 15, 2002 11:49 AM
Subject: Re: [PHP] longitude/latitude function


> I got that from http://freshmeat.net/projects/zipdy/?topic_id=66.  It's a
> program called Zipdy that does these calculations.  There's also a similar
> function on the US government census site (can't remember where though),
but
> I liked Zipdy's better.
>
> --
> Aaron Gould
> [EMAIL PROTECTED]
> Web Developer
> Parts Canada
>
>
> ----- Original Message -----
> From: "Edward Peloke" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Friday, November 15, 2002 11:55 AM
> Subject: RE: [PHP] longitude/latitude function
>
>
> > Thanks Aaron,
> >
> > If you don't mind me asking, where did you get it?  It seems to give a
> > better answer than my function.
> >
> > Thanks!
> > Eddie
> >
> > -----Original Message-----
> > From: Aaron Gould [mailto:[EMAIL PROTECTED]]
> > Sent: Friday, November 15, 2002 11:04 AM
> > To: Edward Peloke; [EMAIL PROTECTED]
> > Subject: Re: [PHP] longitude/latitude function
> >
> >
> > Try this snippet... I can't vouch for its accuracy since I am not a
> > mathematician:
> >
> > <?
> > // Function takes latitude and longitude  of two places as input
> > // and prints the distance in miles and kms.
> > function calculateDistance($lat1, $lon1, $lat2, $lon2)
> >     // Convert all the degrees to radians
> >     $lat1 = deg2rad($lat1);
> >     $lon1 = deg2rad($lon1);
> >     $lat2 = deg2rad($lat2);
> >     $lon2 = deg2rad($lon2);
> >
> >     // Find the deltas
> >     $delta_lat = $lat2 - $lat1;
> >     $delta_lon = $lon2 - $lon1;
> >
> >     // Find the Great Circle distance
> >     $temp = pow(sin($delta_lat / 2.0), 2) + cos($lat1) * cos($lat2) *
> > pow(sin($delta_lon / 2.0), 2);
> >
> >     $EARTH_RADIUS = 3956;
> >
> >     $distance = ($EARTH_RADIUS * 2 * atan2(sqrt($temp), sqrt(1 - $temp))
*
> > 1.6093);
> >
> >     return $distance;
> > }
> > ?>
> >
> >
> > --
> > Aaron Gould
> > [EMAIL PROTECTED]
> > Web Developer
> > Parts Canada
> >
> >
> > ----- Original Message -----
> > From: "Edward Peloke" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Friday, November 15, 2002 11:20 AM
> > Subject: [PHP] longitude/latitude function
> >
> >
> > > Has anyone ever written a php function to take the longitude and
> latitude
> > of
> > > two destinations and calculate the distance?
> > >
> > > I am working on one but the output is just a little off.
> > >
> > > Thanks,
> > > Eddie
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
> > > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to