Quoting Ernest E Vogelsinger <[EMAIL PROTECTED]>:

> At 18:29 20.11.2002, Ryan Gallagher said:
> --------------------[snip]--------------------
> >SELECT * FROM identifisering as i
> >WHERE i.identifiseringid = (
> >    SELECT MAX(ii.identifiseringid) AS maxIdentifiseringid
> >    FROM identifisering as ii
> >  )
> >GROUP BY dprosjekt
> >
> >Now that I look at it, your GROUP BY was definitely out of place, since
> >dprosjekt no doubt is a col being returned from the SELECT * of the main
> >query.
> --------------------[snip]-------------------- 
> 
> No, it wasn't.
> You need the GROUP BY in the subquery to retrieve the max(id) for any
> distinct dprosjekt. If you have it like you did the subquery would simply
> return a single result, the max(id) of all records. Your version simply
> functions as an "order by" which is useless here since only a single record
> will be returned.

Sorry, that's what I was trying to decipher... The '=' combined with the use of
MAX led me to believe the desired recordset size was ONE in the sub query.


-- 
Ryan T. Gallagher
[EMAIL PROTECTED]
International Studies Abroad
http://www.studiesabroad.com
(512)480-8522



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