No, I wasn't going to ask that. But thanks for the info. :P
----- Original Message -----
From: "1LT John W. Holmes" <[EMAIL PROTECTED]>
To: "Stephen" <[EMAIL PROTECTED]>; "Kevin Stone" <[EMAIL PROTECTED]>
Cc: "PHP List" <[EMAIL PROTECTED]>
Sent: Thursday, December 05, 2002 3:14 PM
Subject: Re: [PHP] Looping Addition
> > But then, if the user entered 5 - 6, it should be -1 but it'd return
> > positive one... Is there another way?
>
> Come on, man... this is addition and subtraction. You can't figure it out?
>
> > > You simply need the absolute value of the difference. So taking
> Stephen's
> > > example below..
> > >
> > > $total = 0;
>
> Look, right here, you're setting the total to zero, so now everything will
> be subtracted from zero. If you want everything to be subtracted from the
> first number, the set $total equal to the first number and loop through
the
> remainder.
>
> $total = $_POST['nums'][0];
>
> $cnt = count($_POST['nums']);
> for($x=1;$x<$cnt;$x++)
> { $total -= $_POST['nums'][$x]; }
>
> And I'm sure your next post will be "but how will I use that if I want to
go
> back to addition/multiplication/division???";
>
> Here, assuming $mode can be set to "add","sub","mul" or "div":
>
> $total = $_POST['nums'][0];
> $cnt = count($_POST['nums']);
> for($x=1;$x<$cnt;$x++)
> {
> switch($mode)
> {
> case "add": $total += $_POST['nums'][$x]; break;
> case "sub": $total -= $_POST['nums'][$x]; break;
> case "mul": $total *= $_POST['nums'][$x]; break;
> case "div": $total /= $_POST['nums'][$x]; break;
> }
> }
> echo $total;
>
> Plenty of other ways to do it, too, that may be more efficient. And I
> couldn't honestly tell you if *= and /= work and I don't want to go see.
>
> Hope that helps. Good luck.
>
> ---John Holmes...
>
>
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