Hi,
Friday, December 6, 2002, 5:00:07 AM, you wrote:
S> Hello again,
S> This is another PHP mathematical question. How can I display a bar over a
S> number (overline) if it's a repeating decimal? When the user types in 1 by
S> 3, they get 0.333333333333. I want it to display as 0.3 with the 3
S> overlined. How can I do this keeping in mind that not all numbers will be
S> repeating decimals?
Did this as an exercise :)
function check_to_end($str,$pat){
$lp = strlen($pat);
$ls = strlen($str);
$x = 0;
while(true){
$ls = strlen($str);
if($ls > $lp){//string bigger than pattern
$t = substr($str,0,$lp);
if($t != $pat){
return false;
}
$str = substr($str,$lp);
}else{//pattern too big .. checks tail end
$pat = substr($pat,0,strlen($str));
if( $pat != $str) return false; //no repeat
if($x < 2) return false; //didn't repeat enough
return true; //found a pattern
}
$x++;
}
}
function repeat($num){
$s = substr(number_format($num,16),0,-1); //make a string
echo $s;
list($a,$b) = split('\.',$s); //split decimal bit out
$l = strlen($b);
for($i=0;$i<$l;$i++){ //loop through string
$o = 0;
$k = $b[$i]; //number to find
for($y = $i+1;$y<$l;$y++){ //loop look for same number
$c = ord($b[$y]);
if(ord($k) == ord($b[$y])){ //got a match
$pat = substr($b,$i,$y-$i); //cut out pattern
$str = substr($b,$i); //string to check
if(check_to_end($str,$pat)){ //see if pattern runs
till the end
$o = 1; //yep
if(ord($pat) == ord('0')) $o = 2; //were they
just '0's
break;
}
}
}
if($o)break; // all done
}
if($o == 1){ // a pattern
$r = $a.'.'.substr($b,0,$i).'<span
style="text-decoration:overline">'.$pat.'</span>';
}elseif($o == 2){ // whole bunch of ending 0s
$r = (substr($b,0,$i) != '')? $a.'.'.substr($b,0,$i):$a;
}else{ //no repeat
$r = $s;
}
return $r;
}
//usage
for($x = 1;$x < 100;$x++){
$a = 11/$x;
$res = repeat($a);
echo ' returned: '.$res.'<br>';
}
The check_to_end() function could probably be replaced with a regex but those
go in the same basket as vi with my old brain :)
Regards Tom
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