>> $mysql_result = mysql_query($query, $mysql_link); I am not sure if this is your only problem or not, but mysql_result(); is a function in php. Using a function name as a variable seems like it will just lead to confusion to me. I'd try to avoid it.
>>--> line 36 while($row = mysql_fetch_row($mysql_result)) Anyway, where do you define $row? HTH -Craig >>-----Original Message----- >>From: GWAD Mailinglist [mailto:[EMAIL PROTECTED]] >>Sent: Thursday, December 12, 2002 6:01 PM >>To: [EMAIL PROTECTED] >>Subject: [PHP] MySQL error >> >> >>Hi, >> >>I have following problem: >> >>list.php3 >> >><? >> >> // connect to db >> include("connect_db.php3"); >> >> // get everything from catalog table >> >> $query = "SELECT * FROM yritykset ORDER BY ynimi ASC"; >> >> $mysql_result = mysql_query($query, $mysql_link); >> >> // get each row >> >>--> line 36 while($row = mysql_fetch_row($mysql_result)) >> >> { >> >> //get columns >> >> $id = $row[0]; >> $ynimi = $row[1]; >> $ylahi = $row[2]; >> $ypostios = $row[3]; >> $ypostitmp = $row[11]; >> >> print("<TABLE WIDTH=\"750\" BORDER=\"0\">\n"); >> print("<TR>\n"); >> >> print("<TD WIDTH=\"550\">$ynimi, $ylahi, $ypostios >>$ypostitmp<TD>\n"); >> print("<TD WIDTH=\"200\"><A >>HREF=\"tarkenna.php3?id=$id\">MUOKKAA></A> - <A >>HREF=\"poista.php3?id=$id\">POISTA></A><TD>"); >> >> print("</TR>\n"); >> print("</TABLE>\n"); >> >> } >> >> // disconnect >> mysql_close($mysql_link); >>?> >> >>when run, i'll following error messages: >> >>Warning: mysql_fetch_row(): supplied argument is not a valid MySQL >>result resource in /www/domains/lammidb.phnet.fi/public_html/kaikki.php3 >>on line 36 >> >> >> >>-- >>PHP General Mailing List (http://www.php.net/) >>To unsubscribe, visit: http://www.php.net/unsub.php >> >> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
