I believe you are incorrect. Switch will look for the first case statement
that is true and execute that statement. The following works - case one is
incorrect so it doesn't get executed but the second case does. Paste this
into a test.php file and you will see it works.. Read the manual.
$a=2;
$b=4;
switch (true) {
case ($a < $b) and ($b > 5):
echo "Incorrect";
case ($a == 2):
echo "Correct";
}
So my original question is still stands. The switch statement is correct,
but there is a problem with my conditional statements.
----- Original Message -----
From: "Rick Emery" <[EMAIL PROTECTED]>
To: "Beauford.2002" <[EMAIL PROTECTED]>; "PHP General"
<[EMAIL PROTECTED]>
Sent: Thursday, December 19, 2002 7:33 PM
Subject: Re: [PHP] Another problem with conditional statements
> switch() does not work that way. Switch uses the value in the parentheses
and selects a
> CASE based upon that value. Read the manual.
>
> You will have to use a series of if()-elseif()-else()
> ----- Original Message -----
> From: "Beauford.2002" <[EMAIL PROTECTED]>
> To: "PHP General" <[EMAIL PROTECTED]>
> Sent: Thursday, December 19, 2002 6:19 PM
> Subject: [PHP] Another problem with conditional statements
>
>
> Hi,
>
> This should be as simple as breathing, but not today. I have two variables
> $a and $b which I need to compare in a switch statement in several
different
> ways, but no matter what I do it's wrong.
>
> This is what I have tried, can someone tell me how it should be.
>
> TIA
>
> switch (true):
>
> case ($a == $b): This one seems simple enough.
> do sum stuff;
> break;
>
> case ($a && $b == 124): This appears not to work.
> do sum stuff;
> break;
>
> case ($a == 124 && $b == 755): If $a is equal to 124 and $b is equal
to
> 755 then it should be true..doesn't work.
> do sum stuff;
> break;
>
> case ($a == 124 && $b != 124): Nope, this doesn't appear to work
> either.
> do sum stuff;
> break;
>
> endswitch;
>
>
>
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>
>
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