Hi, the files themselves are available in the $_FILES array, but it's not as simple as that.
may i recommend you start by copying the Examples 18-1 and 18-2 from this page: http://www.php.net/manual/en/features.file-upload.php Once you've got THAT code working smoothly and understand what's happening, THEN start modifying it to a 3-file form. I'd personally push forms through using POST method rather than get whenever possible -- especially when dealing with files... the manual does it this way too :) Justin on 12/01/03 12:18 PM, Kyle Babich ([EMAIL PROTECTED]) wrote: > I just broke skin with php and I'm learning forms, which I'm not good > with at all. These are snippets from post.html: > > <form method="get" action="process.php" enctype="multipart/form-data"> > and > <input type="file" name="image1" maxlength="750" allow="images/*"><br> > <input type="file" name="image2" maxlength="750" allow="images/*"><br> > <input type="file" name="image3" maxlength="750" allow="images/*"><br> > > but how would I pass the actual image on because when I do something like > this: > <?php echo "{$_GET[image1]}"; > ?> > as you could probably guess only the filename prints. > > So how do I take the image instead of just the filename? > > Thank you, > -- > Kyle -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php