php-general Digest 25 Jan 2003 20:33:38 -0000 Issue 1844
Topics (messages 133089 through 133122):
If... Else.. I'm not getting it!
133089 by: Frank Keessen
133091 by: Jason Wong
133092 by: Frank Keessen
133093 by: Johannes Schlueter
133094 by: Frank Keessen
133095 by: Rich Gray
133097 by: Frank Keessen
133114 by: Jason Wong
Re: memory exhausted... memory leak?
133090 by: Tularis
Script under Windows OK, under Linux, not...
133096 by: Daniel Page
133099 by: Daniel Page
Re: Designing My First Content Management System
133098 by: Geckodeep
Re: PHP and XML mailing list
133100 by: Dirkjan Ochtman
Re: Sendmail function
133101 by: Chris Hewitt
Re: Evaluate PHP var in stored sql statement?
133102 by: Noah
133118 by: Maxim Maletsky
133119 by: Noah
PHP 4.3.0 - Apache 2 Problem - Missing phpinfo() Info
133103 by: Kenneth Lerman
OO2relation mapping
133104 by: Dominik Wittenbeck
Re: get apache user
133105 by: Tommy Jensehaugen
133112 by: Jason Wong
Re: [SOAP] Re: soap post and http 1.1 100 continue
133106 by: Danny Shepherd
Switch statement || How to output html without using echo() or print()
133107 by: Noah
133109 by: John W. Holmes
133110 by: Johannes Schlueter
133113 by: Leif K-Brooks
133115 by: Noah
133116 by: Noah
133117 by: Noah
Adjusting Indexed Field After Deleting Entry
133108 by: Guru Geek
question about interaction between own state information...
133111 by: Juerg Zgraggen
GD jpg thumbnail - ugly discollored
133120 by: Victor
133121 by: George E. Papadakis
133122 by: Victor
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----------------------------------------------------------------------
--- Begin Message ---
Hi all,
Please can you help me with the following:
If got a little sample code:
This one is working (!):
<?php
$vname=$_POST['vname'];
echo "hello $vname";
?>
<form action="<? echo ($_SERVER['PHP_SELF']); ?>" method=post>
<table>
<tr><td>Input yourname</td><td><input type=text name=vname></td></tr>
<tr><td colspan=2><input type=submit name=submit></td></tr>
</table>
</form>
<?php
?>
But when i'm using IF Else.. Nothing is happening. I'm only seeing the form but when i
submit that form: The $vname doen't display..
Here is the code that doesn't work:
<?php
$vname=$_POST['vname'];
if($submit) {
echo "hello $vname";
} else {
?>
<form action="<? echo ($_SERVER['PHP_SELF']); ?>" method=post>
<table>
<tr><td>Input yourname</td><td><input type=text name=vname></td></tr>
<tr><td colspan=2><input type=submit name=submit></td></tr>
</table>
</form>
<?php
}
?>
What am I doing wrong???
Thanks,
Frank
--- End Message ---
--- Begin Message ---
On Saturday 25 January 2003 18:27, Frank Keessen wrote:
> But when i'm using IF Else.. Nothing is happening. I'm only seeing the form
> but when i submit that form: The $vname doen't display..
>
> Here is the code that doesn't work:
>
> <?php
> $vname=$_POST['vname'];
> if($submit) {
Try some basic debugging techniques like echo ($submit). You'll see nothing,
hence that IF clause fails.
If register_globals is not enabled then you need to use $_POST['submit'] (just
as you had to use $_POST['vname']).
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
Confidence is simply that quiet, assured feeling you have before you
fall flat on your face.
-- Dr. L. Binder
*/
--- End Message ---
--- Begin Message ---
Hi,
The register_globals = Off. Dit the basic echo ($submit) but it displays
nothing..
Any thoughts somebody??
Thanks for helping me out on this cloudy saturday (in Amsterdam!)
Regards,
Frank
----- Original Message -----
From: "Jason Wong" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 11:36 AM
Subject: Re: [PHP] If... Else.. I'm not getting it!
> On Saturday 25 January 2003 18:27, Frank Keessen wrote:
>
> > But when i'm using IF Else.. Nothing is happening. I'm only seeing the
form
> > but when i submit that form: The $vname doen't display..
> >
> > Here is the code that doesn't work:
> >
> > <?php
> > $vname=$_POST['vname'];
> > if($submit) {
>
> Try some basic debugging techniques like echo ($submit). You'll see
nothing,
> hence that IF clause fails.
>
> If register_globals is not enabled then you need to use $_POST['submit']
(just
> as you had to use $_POST['vname']).
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
>
> /*
> Confidence is simply that quiet, assured feeling you have before you
> fall flat on your face.
> -- Dr. L. Binder
> */
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--- End Message ---
--- Begin Message ---
Hi,
On Saturday 25 January 2003 12:18, Frank Keessen wrote:
> The register_globals = Off. Dit the basic echo ($submit) but it displays
> nothing..
>
> Any thoughts somebody??
Switch on register_globals or (better!) use $_GET['submit'], $_POST['submit']
or $_REQUEST['submit'].
> Thanks for helping me out on this cloudy saturday (in Amsterdam!)
johannes
--- End Message ---
--- Begin Message ---
Hi,
Thanks, but i'm a kind of a newbie in PHP and what i've read it's better to
have the register_globals = Off!!! If you look at my code you see that i'm
using the $_GET variable.. This works fine!! It's the IF.. ELSE what gives
me a lot of trouble!
Frank
----- Original Message -----
From: "Johannes Schlueter" <[EMAIL PROTECTED]>
To: "Frank Keessen" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 12:25 PM
Subject: Re: [PHP] If... Else.. I'm not getting it!
Hi,
On Saturday 25 January 2003 12:18, Frank Keessen wrote:
> The register_globals = Off. Dit the basic echo ($submit) but it displays
> nothing..
>
> Any thoughts somebody??
Switch on register_globals or (better!) use $_GET['submit'],
$_POST['submit']
or $_REQUEST['submit'].
> Thanks for helping me out on this cloudy saturday (in Amsterdam!)
johannes
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--- End Message ---
--- Begin Message ---
You are using the post method not get so $_GET[] should be empty.
Does this version of your code work?
<?php
if(isset($_POST['submit'])) {
$vname=$_POST['vname'];
echo "hello $vname";
} else {
?>
<form action="<? echo ($_SERVER['PHP_SELF']); ?>" method=post>
<table>
<tr><td>Input yourname</td><td><input type=text name=vname></td></tr>
<tr><td colspan=2><input type=submit name=submit></td></tr>
</table>
</form>
<?php
}
?>
Rich
-----Original Message-----
From: Frank Keessen [mailto:[EMAIL PROTECTED]]
Sent: 25 January 2003 11:33
To: Johannes Schlueter; [EMAIL PROTECTED]
Subject: Re: [PHP] If... Else.. I'm not getting it!
Hi,
Thanks, but i'm a kind of a newbie in PHP and what i've read it's better to
have the register_globals = Off!!! If you look at my code you see that i'm
using the $_GET variable.. This works fine!! It's the IF.. ELSE what gives
me a lot of trouble!
Frank
--- End Message ---
--- Begin Message ---
Wow!! It worked... Sorry for the confusion about the get!!
Thanks guys, i can go further!!! Have a nice weekend!
Regards,
Frank
----- Original Message -----
From: "Rich Gray" <[EMAIL PROTECTED]>
To: "Frank Keessen" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 12:42 PM
Subject: RE: [PHP] If... Else.. I'm not getting it!
> You are using the post method not get so $_GET[] should be empty.
>
> Does this version of your code work?
>
> <?php
> if(isset($_POST['submit'])) {
> $vname=$_POST['vname'];
> echo "hello $vname";
> } else {
> ?>
> <form action="<? echo ($_SERVER['PHP_SELF']); ?>" method=post>
> <table>
> <tr><td>Input yourname</td><td><input type=text name=vname></td></tr>
> <tr><td colspan=2><input type=submit name=submit></td></tr>
> </table>
> </form>
> <?php
> }
> ?>
>
> Rich
> -----Original Message-----
> From: Frank Keessen [mailto:[EMAIL PROTECTED]]
> Sent: 25 January 2003 11:33
> To: Johannes Schlueter; [EMAIL PROTECTED]
> Subject: Re: [PHP] If... Else.. I'm not getting it!
>
>
> Hi,
>
> Thanks, but i'm a kind of a newbie in PHP and what i've read it's better
to
> have the register_globals = Off!!! If you look at my code you see that i'm
> using the $_GET variable.. This works fine!! It's the IF.. ELSE what gives
> me a lot of trouble!
>
> Frank
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--- End Message ---
--- Begin Message ---
On Saturday 25 January 2003 19:18, Frank Keessen wrote:
> Hi,
>
> The register_globals = Off. Dit the basic echo ($submit) but it displays
> nothing..
>
> Any thoughts somebody??
> > If register_globals is not enabled then you need to use $_POST['submit']
>
> (just
>
> > as you had to use $_POST['vname']).
!!??!!
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
In matters of principle, stand like a rock;
in matters of taste, swim with the current.
-- Thomas Jefferson
*/
--- End Message ---
--- Begin Message ---
It worked fine till I changed database (just the database-name). Here is
the script that is executed untill the line 61:
- - - GLOBAL.PHP- - -
<?php
// Pre-load vars
$settings = array();
$database = array();
define('XE_VERSION', '0.03a');
define('XE_BUILD', '2003012319');
// Require important Files
require './config.inc.php';
require './libs/error.lib.php';
---------------------------------
- - - CONFIG.INC.PHP - - -
<?php
$database['host'] = 'localhost';
$database['port'] = '3306';
$database['name'] = 'XEngine';
$database['user'] = '';
$database['pass'] = '';
$database['type'] = 'mysql3x';
$database['persistent'] = (bool) false;
$database['status'] = 'off';
$settings['template_type'] = 'file'; // Takes only 'file' or 'db'
$settings['pre'] = 'xe_';
?>
------------------------------
- - - ERROR.LIB.PHP - - -
<?php
class error{
var $cache;
var $last;
var $show;
var $die;
function error(){
$this->cache = array();
$this->last = '';
$this->show = 4;
$this->die = 1;
define('XE_FATAL', 0);
define('XE_ERROR', 1);
define('XE_WARNING', 2);
define('XE_MINOR', 3);
define('XE_NOTICE', 4);
}
function set($show=4, $die=1){
$this->show = $show;
$this->die = $die;
return true;
}
function report($msg, $type){
global $output;
if($type <= $this->show){
$this->cache[] = $type.'-|-'.$msg;
$this->last = $type.'-|-'.$msg;
if($this->die >= $type){
$output->finish();
}
}
return true;
}
function show($which='all'){
$array = array(
0 => 'FATAL ERROR',
1 => 'ERROR',
2 => 'WARNING',
3 => 'MINOR ERROR',
4 => 'NOTICE'
);
if($which=='all'){
foreach($this->cache as $cache){
$errors = explode('-|-', $cache);
$type = $errors[0];
$msg = $errors[1];
// line 61
$return[] = array($array[$type], $msg);
--------------------------------------------------------------------------
I hope you can help me with this, because (on the same server), just 2
dirs away, the same script is running smoothly... :S
- Tularis
John W. Holmes wrote:
Fatal error: Allowed memory size of 8388608 bytes exhausted (tried to
allocate 35 bytes) in
/home/virtual/site8/fst/var/www/html/staff/libs/error.lib.php on line
61
I suddenly got this error on one of my sites, and after rechecking the
script, it shouldn't be happenning :S
Anyway, I was wondering if this would be a memroy leak? or just some
standard notice that I'm taking up too much memory ;)
What were you doing when it happened?
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
--- End Message ---
--- Begin Message ---
Hi,
I have the following code :
$_fp = fopen("/home/dh2240/mgt/index.php", "a+") or die();
$_contents = fread($_fp,filesize("/home/dh2240/mgt/index.php"));
fclose ($_fp);
//Menu elements
$_sme = strpos("$_contents","sub_menu_elements");
echo "sme = $_sme<p>";
...
It should display somthing like "sme = 850", after finding the string in the
specified file.
Under windows, this script works fine (except replacing the
"/home/dh2240/mgt/index.php" by "c:/apache/htdocs/mgt/index.php")... it
seems that the file index.php cannot be opened under linux...
The file is chmod 777, along with the directory /mgt, and the files
identical, but still no luck... The fopen does not die(), but it does not
seem to read any data from the file... I'm confused, and not sure how to
check what is happening... Anyone got any ideas ?
Cheers,
Daniel
--- End Message ---
--- Begin Message ---
It could be somthing to do with my hoster running Linux in Safe Mode... I am
not sure what this could entail, so I'll keep looking. Again, if anyone has
any info, it would be appreciated!!!
Cheers,
Daniel
"Daniel Page" <[EMAIL PROTECTED]> a écrit dans le message news:
[EMAIL PROTECTED]
> Hi,
>
> I have the following code :
>
> $_fp = fopen("/home/dh2240/mgt/index.php", "a+") or die();
> $_contents = fread($_fp,filesize("/home/dh2240/mgt/index.php"));
> fclose ($_fp);
> file://Menu elements
> $_sme = strpos("$_contents","sub_menu_elements");
> echo "sme = $_sme<p>";
> ...
>
> It should display somthing like "sme = 850", after finding the string in
the
> specified file.
>
> Under windows, this script works fine (except replacing the
> "/home/dh2240/mgt/index.php" by "c:/apache/htdocs/mgt/index.php")... it
> seems that the file index.php cannot be opened under linux...
> The file is chmod 777, along with the directory /mgt, and the files
> identical, but still no luck... The fopen does not die(), but it does not
> seem to read any data from the file... I'm confused, and not sure how to
> check what is happening... Anyone got any ideas ?
>
> Cheers,
> Daniel
>
>
--- End Message ---
--- Begin Message ---
I my self is in the same situation I've started of with a great book
http://www.essential-series.com/essential_php.htm which should give you some
idea how to begin and the other one i bought which i am still waiting is
"Building a Database-Driven Web Site Using PHP and MySql" by Kevin Yank.
with these two books you should get head started in CMS.
Good luck.
geckodeep
"Chris Shiflett" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> --- Guru Geek <[EMAIL PROTECTED]> wrote:
> > Does anyone out there have any working examples
> > of a PHP based CMS?
>
> http://freshmeat.net/search/?q=PHP+CMS§ion=projects
>
> Chris
--- End Message ---
--- Begin Message ---
When will this show up at the news server?
"Sterling Hughes" <[EMAIL PROTECTED]> wrote in message
1043463814.795.97.camel@hasele">news:1043463814.795.97.camel@hasele...
> A mailing list for discussing the future of PHP and XML development has
> been created. You can subscribe by sending a message to
> [EMAIL PROTECTED] (normal ezmlm commands apply). This
> mailing list is _only_ intended for actual php extension and api
> development, user support questions should remain on
> [EMAIL PROTECTED]
>
> -Sterling
>
> --
> "Nothing is particularly hard if you divide it into small jobs."
> - Henry Ford
--- End Message ---
--- Begin Message ---
Christian Ista wrote:
Hello,
A friend would like to know how to check on the server (dedicated) if the
function sendmail is enable or not, how ? if not activated how activate ?
Thanks,
If I understand your question correctly (and I may not):
Assuming RedHat linux, then as root "which sendmail" should return you
something like "/usr/sbin/sendmail". This would tell you that it is
installed. "ps ax | grep sendmail" should give you "sendmail: accepting
connections". This would mean that it is running.
If it is installed but not running, then "chkconfig --list sendmail"
will list the runlevels that it is set to run under. Normally it is 2,
3, 4 and 5. "chkconfig --level 2345 sendmail on" will set it to run at
those runlevels, and "service sendmail start" will start it up
immediately if it is not running.
Hope this helps
Chris
--- End Message ---
--- Begin Message ---
Thanks for your help Maxim.
I've got quite a bit to learn. PHP is far more challenging than Cold
Fusion.........
--Noah
----- Original Message -----
From: "Maxim Maletsky" <[EMAIL PROTECTED]>
To: "Noah" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Friday, January 24, 2003 11:02 AM
Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
>
> eval takes the string and executes PHP in that string. So,
>
> eval("\$myrow[2] = \"$myrow[2]\";");
>
> is equivalent to:
>
> $myrow[2] = "$myrow[2]";
>
> I'd reccomend you using single quotes and then escape only backslashes
> and single quotes within a string
>
> --
> Maxim Maletsky
> [EMAIL PROTECTED]
>
>
>
> "Noah" <[EMAIL PROTECTED]> wrote... :
>
> > Don't quite understand why this works, but it does:
> >
> > /* Escape quotes in sql_query so our header_id gets evaluated */
> > eval("\$myrow[2] = \"$myrow[2]\";");
> >
> > What's the deal with the leading backslash in ' eval("\$myrow[2] '?
> >
> > Does eval() tell php to evaluate the string as php code; i.e. text
without
> > quotes?
> >
> > Thanks for the help.......
> >
> > --Noah
> >
> >
> > ----- Original Message -----
> > From: "Maxim Maletsky" <[EMAIL PROTECTED]>
> > To: "CF High" <[EMAIL PROTECTED]>
> > Cc: <[EMAIL PROTECTED]>
> > Sent: Friday, January 24, 2003 9:59 AM
> > Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
> >
> >
> > >
> > > use eval()
> > >
> > > www.php.net/eval
> > >
> > >
> > > --
> > > Maxim Maletsky
> > > [EMAIL PROTECTED]
> > >
> > >
> > >
> > > "CF High" <[EMAIL PROTECTED]> wrote... :
> > >
> > > > Hey all.
> > > >
> > > > I need to find out how to get PHP to evaluate a PHP variable stored
in
> > our
> > > > MySql database.
> > > >
> > > > Currently the variable is being read as a string; i.e. select * from
> > table
> > > > where column = $myrow[0] -- instead of evaluating $myrow[0] as a
> > variable.
> > > >
> > > >
> > > > The SQL statement is retrieved in the first call to dbConnect (see
code
> > > > below)
> > > >
> > > >
> > > >
> > > > dbConnect("SELECT header_id, header, sql_query FROM cat_headers
WHERE
> > > > section_id = $_REQUEST[section_id] order by header");
> > > >
> > > > $set = $result; /* Give initial result set a unique name */
> > > >
> > > > while ($myrow = mysql_fetch_row($set)) {
> > > >
> > > > echo(Display the header title here);
> > > >
> > > >
> > > > dbConnect($myrow[2]); /* $myrow[2] is the sql_query
> > gotten
> > > > from the first dbConnect() call */
> > > >
> > > > $set1 = $result; /* Give next result set a unique
name
> > */
> > > >
> > > > while ($myrow = mysql_fetch_row($set1)) {
> > > >
> > > > echo(Display category rows here);
> > > >
> > > > }
> > > >
> > > > }
> > > >
> > > > --
> > > > Any leads/suggestions much appreciated..........
> > > >
> > > > --Noah
> > > >
> > > >
> > > >
> > > > --
> > > > PHP General Mailing List (http://www.php.net/)
> > > > To unsubscribe, visit: http://www.php.net/unsub.php
> > > >
> > >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
>
--- End Message ---
--- Begin Message ---
no, much less instead
---
Maxim Maletsky
[EMAIL PROTECTED]
On Sat, 25 Jan 2003 09:18:47 -0800 "Noah" <[EMAIL PROTECTED]> wrote:
> Thanks for your help Maxim.
>
> I've got quite a bit to learn. PHP is far more challenging than Cold
> Fusion.........
>
> --Noah
>
> ----- Original Message -----
> From: "Maxim Maletsky" <[EMAIL PROTECTED]>
> To: "Noah" <[EMAIL PROTECTED]>
> Cc: <[EMAIL PROTECTED]>
> Sent: Friday, January 24, 2003 11:02 AM
> Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
>
>
> >
> > eval takes the string and executes PHP in that string. So,
> >
> > eval("\$myrow[2] = \"$myrow[2]\";");
> >
> > is equivalent to:
> >
> > $myrow[2] = "$myrow[2]";
> >
> > I'd reccomend you using single quotes and then escape only backslashes
> > and single quotes within a string
> >
> > --
> > Maxim Maletsky
> > [EMAIL PROTECTED]
> >
> >
> >
> > "Noah" <[EMAIL PROTECTED]> wrote... :
> >
> > > Don't quite understand why this works, but it does:
> > >
> > > /* Escape quotes in sql_query so our header_id gets evaluated */
> > > eval("\$myrow[2] = \"$myrow[2]\";");
> > >
> > > What's the deal with the leading backslash in ' eval("\$myrow[2] '?
> > >
> > > Does eval() tell php to evaluate the string as php code; i.e. text
> without
> > > quotes?
> > >
> > > Thanks for the help.......
> > >
> > > --Noah
> > >
> > >
> > > ----- Original Message -----
> > > From: "Maxim Maletsky" <[EMAIL PROTECTED]>
> > > To: "CF High" <[EMAIL PROTECTED]>
> > > Cc: <[EMAIL PROTECTED]>
> > > Sent: Friday, January 24, 2003 9:59 AM
> > > Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
> > >
> > >
> > > >
> > > > use eval()
> > > >
> > > > www.php.net/eval
> > > >
> > > >
> > > > --
> > > > Maxim Maletsky
> > > > [EMAIL PROTECTED]
> > > >
> > > >
> > > >
> > > > "CF High" <[EMAIL PROTECTED]> wrote... :
> > > >
> > > > > Hey all.
> > > > >
> > > > > I need to find out how to get PHP to evaluate a PHP variable stored
> in
> > > our
> > > > > MySql database.
> > > > >
> > > > > Currently the variable is being read as a string; i.e. select * from
> > > table
> > > > > where column = $myrow[0] -- instead of evaluating $myrow[0] as a
> > > variable.
> > > > >
> > > > >
> > > > > The SQL statement is retrieved in the first call to dbConnect (see
> code
> > > > > below)
> > > > >
> > > > >
> > > > >
> > > > > dbConnect("SELECT header_id, header, sql_query FROM cat_headers
> WHERE
> > > > > section_id = $_REQUEST[section_id] order by header");
> > > > >
> > > > > $set = $result; /* Give initial result set a unique name */
> > > > >
> > > > > while ($myrow = mysql_fetch_row($set)) {
> > > > >
> > > > > echo(Display the header title here);
> > > > >
> > > > >
> > > > > dbConnect($myrow[2]); /* $myrow[2] is the sql_query
> > > gotten
> > > > > from the first dbConnect() call */
> > > > >
> > > > > $set1 = $result; /* Give next result set a unique
> name
> > > */
> > > > >
> > > > > while ($myrow = mysql_fetch_row($set1)) {
> > > > >
> > > > > echo(Display category rows here);
> > > > >
> > > > > }
> > > > >
> > > > > }
> > > > >
> > > > > --
> > > > > Any leads/suggestions much appreciated..........
> > > > >
> > > > > --Noah
> > > > >
> > > > >
> > > > >
> > > > > --
> > > > > PHP General Mailing List (http://www.php.net/)
> > > > > To unsubscribe, visit: http://www.php.net/unsub.php
> > > > >
> > > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
> > > To unsubscribe, visit: http://www.php.net/unsub.php
> > >
> >
>
--- End Message ---
--- Begin Message ---
Hmmmmm......
Guess I'll find out as I go deeper into PHP........
--Noah
----- Original Message -----
From: "Maxim Maletsky" <[EMAIL PROTECTED]>
To: "Noah" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 9:47 AM
Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
> no, much less instead
>
> ---
> Maxim Maletsky
> [EMAIL PROTECTED]
>
>
> On Sat, 25 Jan 2003 09:18:47 -0800 "Noah" <[EMAIL PROTECTED]> wrote:
>
> > Thanks for your help Maxim.
> >
> > I've got quite a bit to learn. PHP is far more challenging than Cold
> > Fusion.........
> >
> > --Noah
> >
> > ----- Original Message -----
> > From: "Maxim Maletsky" <[EMAIL PROTECTED]>
> > To: "Noah" <[EMAIL PROTECTED]>
> > Cc: <[EMAIL PROTECTED]>
> > Sent: Friday, January 24, 2003 11:02 AM
> > Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
> >
> >
> > >
> > > eval takes the string and executes PHP in that string. So,
> > >
> > > eval("\$myrow[2] = \"$myrow[2]\";");
> > >
> > > is equivalent to:
> > >
> > > $myrow[2] = "$myrow[2]";
> > >
> > > I'd reccomend you using single quotes and then escape only backslashes
> > > and single quotes within a string
> > >
> > > --
> > > Maxim Maletsky
> > > [EMAIL PROTECTED]
> > >
> > >
> > >
> > > "Noah" <[EMAIL PROTECTED]> wrote... :
> > >
> > > > Don't quite understand why this works, but it does:
> > > >
> > > > /* Escape quotes in sql_query so our header_id gets evaluated */
> > > > eval("\$myrow[2] = \"$myrow[2]\";");
> > > >
> > > > What's the deal with the leading backslash in ' eval("\$myrow[2] '?
> > > >
> > > > Does eval() tell php to evaluate the string as php code; i.e. text
> > without
> > > > quotes?
> > > >
> > > > Thanks for the help.......
> > > >
> > > > --Noah
> > > >
> > > >
> > > > ----- Original Message -----
> > > > From: "Maxim Maletsky" <[EMAIL PROTECTED]>
> > > > To: "CF High" <[EMAIL PROTECTED]>
> > > > Cc: <[EMAIL PROTECTED]>
> > > > Sent: Friday, January 24, 2003 9:59 AM
> > > > Subject: Re: [PHP] Evaluate PHP var in stored sql statement?
> > > >
> > > >
> > > > >
> > > > > use eval()
> > > > >
> > > > > www.php.net/eval
> > > > >
> > > > >
> > > > > --
> > > > > Maxim Maletsky
> > > > > [EMAIL PROTECTED]
> > > > >
> > > > >
> > > > >
> > > > > "CF High" <[EMAIL PROTECTED]> wrote... :
> > > > >
> > > > > > Hey all.
> > > > > >
> > > > > > I need to find out how to get PHP to evaluate a PHP variable
stored
> > in
> > > > our
> > > > > > MySql database.
> > > > > >
> > > > > > Currently the variable is being read as a string; i.e. select *
from
> > > > table
> > > > > > where column = $myrow[0] -- instead of evaluating $myrow[0] as a
> > > > variable.
> > > > > >
> > > > > >
> > > > > > The SQL statement is retrieved in the first call to dbConnect
(see
> > code
> > > > > > below)
> > > > > >
> > > > > >
> > > > > >
> > > > > > dbConnect("SELECT header_id, header, sql_query FROM cat_headers
> > WHERE
> > > > > > section_id = $_REQUEST[section_id] order by header");
> > > > > >
> > > > > > $set = $result; /* Give initial result set a unique name
*/
> > > > > >
> > > > > > while ($myrow = mysql_fetch_row($set)) {
> > > > > >
> > > > > > echo(Display the header title here);
> > > > > >
> > > > > >
> > > > > > dbConnect($myrow[2]); /* $myrow[2] is the
sql_query
> > > > gotten
> > > > > > from the first dbConnect() call */
> > > > > >
> > > > > > $set1 = $result; /* Give next result set a
unique
> > name
> > > > */
> > > > > >
> > > > > > while ($myrow = mysql_fetch_row($set1)) {
> > > > > >
> > > > > > echo(Display category rows here);
> > > > > >
> > > > > > }
> > > > > >
> > > > > > }
> > > > > >
> > > > > > --
> > > > > > Any leads/suggestions much appreciated..........
> > > > > >
> > > > > > --Noah
> > > > > >
> > > > > >
> > > > > >
> > > > > > --
> > > > > > PHP General Mailing List (http://www.php.net/)
> > > > > > To unsubscribe, visit: http://www.php.net/unsub.php
> > > > > >
> > > > >
> > > >
> > > >
> > > > --
> > > > PHP General Mailing List (http://www.php.net/)
> > > > To unsubscribe, visit: http://www.php.net/unsub.php
> > > >
> > >
> >
>
--- End Message ---
--- Begin Message ---
phpinfo() on PHP Version 4.2.2 with Apache/1.3.24 has a block which called
Apache Environment which does not appear in PHP 4.3.0/Apache2.
This block of info has (in part):
DOCUMENT_ROOT /usr/local/apache/htdocs_best-emts
HTTP_ACCEPT image/gif, image/x-xbitmap, image/jpeg, image/pjpeg,
application/vnd.ms-powerpoint, application/vnd.ms-excel, application/msword,
*/*
HTTP_ACCEPT_ENCODING gzip, deflate
HTTP_ACCEPT_LANGUAGE en-us
HTTP_CONNECTION Keep-Alive
HTTP_COOKIE POSTNUKESID=af2005c09ffd2e5ceecf91eff96ee77d
HTTP_HOST www.best-emts.com
HTTP_REFERER
http://www.best-emts.com/modules.php?op=modload&name=PostWrap&file=index&pag
e=http://www.best-emts.com/emts/rosterByNumber.php
HTTP_USER_AGENT Mozilla/4.0 (compatible; MSIE 6.0; Windows 98)
PATH
/usr/local/bin:/bin:/usr/bin:/usr/X11R6/bin:/usr/local/bin:/usr/local/java/b
in:/bd/EMTS/bin:/usr/local/map/bin:/usr/local/mysql/bin
REMOTE_ADDR 198.138.213.31
REMOTE_PORT 2010
SCRIPT_FILENAME /usr/local/apache/htdocs_best-emts/emts/rosterByNumber.php
SERVER_ADDR 198.138.213.25
------------------------------------------
Some of the information does not seem to be available elsewhere.
Is this an undocumented change? Is this a bug in my configuration? What,
if anything, am I doing wrong?
Thanks,
Ken
Kenneth Lerman [EMAIL PROTECTED]
Systems Essentials Limited Fax: (203)426-9138
55 Main Street Voice: (203)426-4430
Newtown, CT 06470 http://se-ltd.com/~lerman
--- End Message ---
--- Begin Message ---
Quick question for the skilled among you,
Why I ask this:
I am currently developing a object to relational mapping layer for PHP. It's
NOT a simple treat all databases like one kind of layer (although it does
involve it to preserve extensibility) but an XML based intermediate layer
that creates both, table structures, following a conventional scheme and PHP
classes that allow, OO access to these tables.
I have enclosed the XML file that represents the intermediate layer. Its
pretty readable even without the XML schema.
I am currently under development, so don't expect anything useful in less
than a few weeks
Question:
Does anyone of you know anyone who has tried something similar, because my
research on the subject grows thin? Is something like this of public
interest at all, or would you prefer accessing your datastructure the old
fashion way?
Dominik Wittenbeck
----------------------------------------------------------------
http://www.developaz.com
begin 666 oo2relationalMapping.xml
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+/"]D871A8F%S93X`
`
end
--- End Message ---
--- Begin Message ---
If I can't use any of those, it's not possible? correct?
thank you for your help.
tommy
"Jason Wong" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> On Saturday 25 January 2003 06:15, Tommy Jensehaugen wrote:
>
> > I have a page where I log in as an Apache user. How do I get the apache
> > username in php?
>
> print_r($_SERVER) to see which you can use.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
>
> /*
> Thirteen at a table is unlucky only when the hostess has only twelve
chops.
> -- Groucho Marx
> */
>
--- End Message ---
--- Begin Message ---
On Saturday 25 January 2003 23:41, Tommy Jensehaugen wrote:
> "Jason Wong" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>
> > On Saturday 25 January 2003 06:15, Tommy Jensehaugen wrote:
> > > I have a page where I log in as an Apache user. How do I get the apache
> > > username in php?
> >
> > print_r($_SERVER) to see which you can use.
> If I can't use any of those, it's not possible? correct?
> thank you for your help.
I'm assuming you're using HTTP authentication? So create a php page which
requires login, then on that page do the above. That will show you all the
values that can be obtained from apache.
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
The goys have proven the following theorem...
-- Physicist John von Neumann, at the start of a classroom
lecture.
*/
--- End Message ---
--- Begin Message ---
----- Original Message -----
From: "Dominik Wittenbeck" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 3:28 PM
Subject: [SOAP] Re: soap post and http 1.1 100 continue
> Yep, know that one,
>
> Why it does happen:
> although the HTTP 1.1 spec states that a HTTP 100 SHOULD NOT (or was it
MUST
> NOT ;-) to the client, unless it requires it by a specific header, IIS
does
> it with webservices and thereby about any that are published and
maintained
> with .NET ;-)
Not quite right :
An origin server SHOULD NOT send a 100 (Continue) response if the request
message does not include an Expect request-header field with the
"100-continue" expectation, and MUST NOT send a 100 (Continue) response if
such a request comes from an HTTP/1.0 (or earlier) client. There is an
exception to this rule: for compatibility with RFC 2068, a server MAY send a
100 (Continue) status in response to an HTTP/1.1 PUT or POST request that
does not include an Expect request-header field with the "100-continue"
expectation. This exception, the purpose of which is to minimize any client
processing delays associated with an undeclared wait for 100 (Continue)
status, applies only to HTTP/1.1 requests, and not to requests with any
other HTTP-version value.
> Solution:
> A HTTP 100 basically states: "ok I am ready for your content now". You
have
> probably submitted your content already... resend it, but the content
only,
> without the \r\n\r\n mark that separates headers from payload with HTTP.
> To serve a clean solution you should however go ahead and implement a
> listener that tries to hear a HTTP 100. With PHP this is kind of tiresome.
> In my implementation I also just resend the payload ;-)
A HTTP 100 basically states "ok based on your headers I won't reject your
body data, so send it now" - handy for services which need to check specific
headers. Imagine if the client sent 5MBs of data only to have it knocked
back because an authorization header wasn't present. :-)
I suppose a better solution would be to use the 100-Continue properly (i.e.
send headers + with an expect header and no body) or send HTTP/1.0 requests.
HTH
Danny.
--- End Message ---
--- Begin Message ---
Hey all.
Don't know if this is possible, but here goes:
I've got a simple switch statement that carries out one of several
operations based on the switch statement variable value.
Each operation has @ 50 lines of html -- do I have to echo or print all this
html!?
I'm new to PHP so pardon my ignorance here. I'm used to the relative ease
of Cold Fusion............
Thanks for any ideas/suggestions,
--Noah
--
--- End Message ---
--- Begin Message ---
> I've got a simple switch statement that carries out one of several
> operations based on the switch statement variable value.
>
> Each operation has @ 50 lines of html -- do I have to echo or print
all
> this
> html!?
You could put your HTML into a separate file and just include() it
wherever you want it displayed...
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
--- End Message ---
--- Begin Message ---
On Saturday 25 January 2003 20:38, CF High wrote:
> Each operation has @ 50 lines of html -- do I have to echo or print all
> this html!?
Try something like
<?php
switch ($foo) {
case 1:
?>
<h1>Hello</h1>
<?php
break;
}
?>
johannes
--- End Message ---
--- Begin Message ---
No. You can either echo/print with a heredoc (which is still
echoing/printing, but is a lot easier) or you can exit PHP. For example:
<?php
switch($somevar){
case 'case1':
print <<< END
some html
some html
some html
END;
break;
case 'case2':
print <<< END
some html
some html
some html
END;
break;
}
?>
Or:
<?php
switch($somevar){
case 'case1':
?>
some html
some html
some html
<?php
break;
case 'case2':
?>
some html
some html
some html
<?php
break;
}
?>
CF High wrote:
Hey all.
Don't know if this is possible, but here goes:
I've got a simple switch statement that carries out one of several
operations based on the switch statement variable value.
Each operation has @ 50 lines of html -- do I have to echo or print all this
html!?
I'm new to PHP so pardon my ignorance here. I'm used to the relative ease
of Cold Fusion............
Thanks for any ideas/suggestions,
--Noah
--
--
The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law.
--- End Message ---
--- Begin Message ---
That does the trick, although I'm not exactly sure why.
Shouldn't the html between the <?php case 1: ?> and <?php break; }: ?>
statements be executed regardless of whether or not case 1 matches the
switch variable?
In Cold Fusion anything outside of <cfoutput>cf code here</cfoutput> is
ignored by the CF language processor; thus the <?php case 1?> html here
<?php break; }?> would display the html for each case.
In any case thanks for workaround -- I would have echoed out all the html
otherwise..........
--Noah
----- Original Message -----
From: "Johannes Schlueter" <[EMAIL PROTECTED]>
To: "CF High" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 8:38 AM
Subject: Re: [PHP] Switch statement || How to output html without using
echo() or print()
> On Saturday 25 January 2003 20:38, CF High wrote:
>
> > Each operation has @ 50 lines of html -- do I have to echo or print all
> > this html!?
>
> Try something like
> <?php
> switch ($foo) {
> case 1:
> ?>
> <h1>Hello</h1>
> <?php
> break;
> }
> ?>
>
> johannes
>
--- End Message ---
--- Begin Message ---
Hey John.
While your suggestion certainly will work, I'd prefer not to have an
excessive number of include files to keep track of.
Johannes' suggestion does the trick:
"Try something like
<?php
switch ($foo) {
case 1:
?>
<h1>Hello</h1>
<?php
break;
}
?>"
----- Original Message -----
From: "John W. Holmes" <[EMAIL PROTECTED]>
To: "'CF High'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 8:42 AM
Subject: RE: [PHP] Switch statement || How to output html without using
echo() or print()
> > I've got a simple switch statement that carries out one of several
> > operations based on the switch statement variable value.
> >
> > Each operation has @ 50 lines of html -- do I have to echo or print
> all
> > this
> > html!?
>
> You could put your HTML into a separate file and just include() it
> wherever you want it displayed...
>
> ---John W. Holmes...
>
> PHP Architect - A monthly magazine for PHP Professionals. Get your copy
> today. http://www.phparch.com/
>
>
--- End Message ---
--- Begin Message ---
Thanks for the informative response, Leif.
Looks like you and Johannes are on the same page -- these solutions save a
great deal of time.
Thanks,
--Noah
"Leif K-Brooks" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> No. You can either echo/print with a heredoc (which is still
> echoing/printing, but is a lot easier) or you can exit PHP. For example:
> <?php
> switch($somevar){
> case 'case1':
> print <<< END
> some html
> some html
> some html
> END;
> break;
> case 'case2':
> print <<< END
> some html
> some html
> some html
> END;
> break;
> }
> ?>
>
>
> Or:
> <?php
> switch($somevar){
> case 'case1':
> ?>
> some html
> some html
> some html
> <?php
> break;
> case 'case2':
> ?>
> some html
> some html
> some html
> <?php
> break;
> }
> ?>
>
> CF High wrote:
>
> >Hey all.
> >
> >Don't know if this is possible, but here goes:
> >
> >I've got a simple switch statement that carries out one of several
> >operations based on the switch statement variable value.
> >
> >Each operation has @ 50 lines of html -- do I have to echo or print all
this
> >html!?
> >
> >I'm new to PHP so pardon my ignorance here. I'm used to the relative
ease
> >of Cold Fusion............
> >
> >Thanks for any ideas/suggestions,
> >
> >--Noah
> >
> >--
> >
> >
> >
> >
> >
> >
>
> --
> The above message is encrypted with double rot13 encoding. Any
unauthorized attempt to decrypt it will be prosecuted to the full extent of
the law.
>
>
>
--- End Message ---
--- Begin Message ---
Hello,
Here is one of my smaller PHP projects. I'm trying to finish it before
I move on to my CMS project.
http://www.g-i-w-s.com/linker_admin.php
The script does nothing more then manage links. It lists an indexed
number of the link, a url, a text description and a delete option.
Here's my question. I originally had a link #1, #2, and #3. I
obviously deleted them. I was wondering if there is a way to use
PHP/MySQL to get the indexed numbers to re-assign so that the first link
you see is always #1 the second link you see is always #2 and so on?
Thanks in advance,
Roger
PS
The original script was not mine, it came from a 'php how to' article at
web monkey, I did some modifications to fit what I needed. We don't
want anyone thinking that I'm taking credit for their knowledge ;-)
--- End Message ---
--- Begin Message ---
hi
question about interaction between own state information...
my problem is very simple:
i have an object with a class-member-function which writes a file of about
2MB. the duration of this function is quite long. thats why i'd like to have
display informations in a pop-up. for that reason i made a member-variable
for getting a counter and set the object into a registerd session. the
running writefunction will now increase the counter every time it wirtes
information to the file. on the other hand, the pop-up should access the
same session and read the counter-variable on the object with the running
wirtefunction.
my problem:
i cannot access the session on the pop-up WHILE the writefile function is
running. that writefile function is locking the session in some way. that
seems logical for me.
now, how can solve my problem? my main-window should be able to interact
with its pop-up-window. i would like to send state information from a
running function on the main-window to its pop-up-window. this is refreshing
automatically.
Thanx for every hint or answer
Regards,
Jürg Zgraggen
--- End Message ---
--- Begin Message ---
I have a script that takes uploaded images (jpeg only) and makes
proportionate thumbnails etc, and saves them in jpeg (.jpg) format again
(default compression of %75 I think) anyway, the thumbnails are UGLY.
Beauty of content aside, they are discolored, and usually one
predominant color takes over the entire picture so they come looking
like off-black and white thumbnails. WHY? And how can I fix this/get
around it?
This is some extra info.
GD Support enabled
GD Version 2.0 or higher
FreeType Support enabled
FreeType Linkage with freetype
JPG Support enabled
PNG Support enabled
WBMP Support enabled
______________________________________________________________________
Post your free ad now! http://personals.yahoo.ca
--- End Message ---
--- Begin Message ---
Use ImageMagick found @ http://www.imagemagick.org .
It is all you need to handle images.
Aside the binary external program take a look at this too :
http://magick.communityconnect.com/
best of luck,
--georgep
----- Original Message -----
From: "Victor" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 10:00 PM
Subject: [PHP] GD jpg thumbnail - ugly discollored
> I have a script that takes uploaded images (jpeg only) and makes
> proportionate thumbnails etc, and saves them in jpeg (.jpg) format again
> (default compression of %75 I think) anyway, the thumbnails are UGLY.
> Beauty of content aside, they are discolored, and usually one
> predominant color takes over the entire picture so they come looking
> like off-black and white thumbnails. WHY? And how can I fix this/get
> around it?
>
> This is some extra info.
>
> GD Support enabled
> GD Version 2.0 or higher
> FreeType Support enabled
> FreeType Linkage with freetype
> JPG Support enabled
> PNG Support enabled
> WBMP Support enabled
>
>
>
> ______________________________________________________________________
> Post your free ad now! http://personals.yahoo.ca
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--- End Message ---
--- Begin Message ---
That is not an option since I do not have control over the hosting
company.
-----Original Message-----
From: George E. Papadakis [mailto:[EMAIL PROTECTED]]
Sent: Saturday, January 25, 2003 3:20 PM
To: Victor; [EMAIL PROTECTED]
Subject: Re: [PHP] GD jpg thumbnail - ugly discollored
Use ImageMagick found @ http://www.imagemagick.org .
It is all you need to handle images.
Aside the binary external program take a look at this too :
http://magick.communityconnect.com/
best of luck,
--georgep
----- Original Message -----
From: "Victor" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, January 25, 2003 10:00 PM
Subject: [PHP] GD jpg thumbnail - ugly discollored
> I have a script that takes uploaded images (jpeg only) and makes
> proportionate thumbnails etc, and saves them in jpeg (.jpg) format
again
> (default compression of %75 I think) anyway, the thumbnails are UGLY.
> Beauty of content aside, they are discolored, and usually one
> predominant color takes over the entire picture so they come looking
> like off-black and white thumbnails. WHY? And how can I fix this/get
> around it?
>
> This is some extra info.
>
> GD Support enabled
> GD Version 2.0 or higher
> FreeType Support enabled
> FreeType Linkage with freetype
> JPG Support enabled
> PNG Support enabled
> WBMP Support enabled
>
>
>
> ______________________________________________________________________
> Post your free ad now! http://personals.yahoo.ca
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
______________________________________________________________________
Post your free ad now! http://personals.yahoo.ca
--- End Message ---
