> ### <?php
> ### // process form
> ### $link = mysql_connect("localhost", "root");
> you need to have the password as the third argument
> $link = mysql_connect("localhost", "root", "password");
>
> Also, why is it in a variable?
> Just make it:
> mysql_connect("localhost", "root", "password");
Sometime there are users that do not have a password. Every parameter to
mysql_connect() is optional, by the way.
Also, you want to assign the result of mysql_connect() to a variable so
you can tell the connections apart. If you only have one connection per
script, then it's not a big deal. But, if you connect to several
databases, then you need that result to tell them apart when you do
queries later so PHP knows what connection to send your query through.
> ### mysql_select_db("mydb",$db);
> ### $sql = "INSERT INTO agenda (nombre, direccion, telefono, email) "
+
Problem is the plus (+) sign at the end of this line.
---John W. Holmes...
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