if ($array = mysql_fetcharray($result))
{ echo $array["SUM( hide = 0 )"];
}
although for readability I'd prefer an
" AS sum_hide " in the query and then use
$array["sum_hide"]
in general for reading from a mysql result ...
// for a single return row (or the just the first row)
if ($result = mysql_query("..."))
{ if ($array = mysql_fetch_array($result))
{ ...
}
}
// for multiple return rows
if ($result = mysql_query("..."))
{ while ($array = mysql_fetch_array($result))
{ ...
}
}
Tim Ward
http://www.chessish.com
mailto:[EMAIL PROTECTED]
----- Original Message -----
From: rentAweek support <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, February 27, 2003 5:31 PM
Subject: [PHP] Counting table fields having specific values
> I have a table where the row named "hide" can have a value 0 or 1.
> I want to obtain a count of all the rows where "hide" has value 0.
>
> The following works on mysqladmin:
>
> SELECT SUM( hide = 0 ) FROM `names` LIMIT 0, - 1
>
> Giving
>
> SUM( hide = 0 )
> 7
>
> The PHP script statements generated are:
>
> $sql = 'SELECT SUM( hide = 0 ) FROM `names` LIMIT 0, -1';
> $result = mysql_query($sql);
>
> What assignment statement do I need to write now to obtain the SUM value
> as shown by mysqladmin please?
>
> TIA
>
> Mike
>
>
>
>
>
>
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