[PHP] transferring another .jpg to your own

[Anthony Ritter]

Using PHP 4.1.1. / Apache / Win 98

I'd like to use a .jpg from another URL - say:

http://www.blah.com/foo.jpg

and turn it into a variable using PHP and then once it is a variable to try
to manipulate that image using GD Libraries which are installed.

Is this possible?

I tried placing the string of the URL into a variable like:

$theoldimage="http://www.blah.com/foo.jpg";;

and then calling this function of:

$thenewimage=imagecreatefromjpeg ($theoldimage);

but it did not return a value when I echo'ed

$thenewimage

Many thanks for any advice.
Tony Ritter
..................................................................

function LoadJpeg ($imgname) {
    $im = @imagecreatefromjpeg ($imgname); /* Attempt to open */
    if (!$im) { /* See if it failed */
        $im  = imagecreate (150, 150); /* Create a blank image */
        $bgc = imagecolorallocate ($im, 255, 255, 255);
        $tc  = imagecolorallocate ($im, 0, 0, 0);
        imagefilledrectangle ($im, 0, 0, 150, 30, $bgc);
        /* Output an errmsg */
        imagestring ($im, 1, 5, 5, "Error loading $imgname", $tc);
    }
    return $im;
}




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