--- In php-list@yahoogroups.com, James Keeline <[EMAIL PROTECTED]> wrote: > > --- whoisquilty <[EMAIL PROTECTED]> wrote: > > > Thanks, James. What if I want to pass $out to another page? I tried that and > > since my $out has code in it, the page is reading it as code and not as a > > variable in a link. > > > > Jeremy > > Most of the time PHP is used to generate custom HTML. Some of that custom > content is determined by the logic of the program and some may come from a > database query or other resource. > > If you are generating a block of content (text + HTML) you can best pass it > from one page to another using session variables. > > The basic procedure in PHP is to start your opening PHP tag (<?php) start on > the first line on the first character position. Then do a session_start(), > build up your $out variable, and save it in a session variable. > > _____ > <?php > session_start(); > $out = ""; > $out .= "first line<br />\n"; > $out .= "second line<br />\n"; > # ... > $_SESSION['html'] = $out; > ?> > > The underscores are not part of the file of course. It's important that you > do > not do any print or echo statements before you save the value in the $_SESSION > superglobal. > > In your second page you do something similar: > _____ > <?php > session_start(); > $html = $_SESSION['html']; > > print $html; > ?> > > James >
That works. Thank you, James!
