--- In php-list@yahoogroups.com, HELLBOY <[EMAIL PROTECTED]> wrote:
>
> > On Wed, Nov 12, 2008 at 11:55 AM, brucewhealton
> > wrote:
>
> > Hello all,
> > I thought this would be very easy but I'm doing something
> > wrong here. I want to create a display of an image using a variable.
> > In static html it is
> > <img src="images/topbanner1.jpg" />
> >
> > I want the topbanner to change depending on the month of the year.
> > So, I calculate that with this, easy enough:
> > <?php
> > $monthnum = data("n");
> > ?>
> >
> > I have six banners so I if $monthnum is greater than 6, I subtract 6.
> > This so far is very easy.
> >
> > Now, I want to build up the image tag using the php values. So, I
> > have the following (this is just the part of the code for displaying
> > the image.
> >
> > echo "<img src=\"images/topbanner";
> > echo $monthnum."jpg";
> > echo "\"/>";
> >
> > I used the \ to escape the " on the first line where it should be
> > src="images/topbanner"
> >
> > What's wrong here?
> > Thanks,
> > Bruce
> >
> ------------------------------
> try this
> echo "<img src='images/topbanner".$monthnum.".jpg'/>";
> I hope it will help.
>
>
> --
> http://phpinterviewanswers.blogspot.com/
>
-----------------------------------
Yep. I was missing the . before jpg.
Thanks,
Bruce
